The value of q in p2= 0.49 is A.
0.49(2x0.7xq)+q2=1
1.4qxq2=0.51
1.4qxq=0.714
q+q=0.510
q=0.26
round it up to 3
Answer:
Thirty patients with acne volunteer to be treated with either a medicinal lotion
or a normal moisturizing cream. This type of experimental design is called
a clinical trial.-B.
If a homozygous dominant dog with brown fur is crossed with a heterozygous dog with brown fur, then the percentage of possible genotypes is 50% pure dominant and 50% heterozygous
How to find out?
First, we have to group them for easy identification.
BB = Homozogous dominant
Bb = Heterozygous
Then the two are crossed to become:
BB x Bb
Then obtained:
B B
B BB BB
b Bb Bb
From the results of the crosses above, it can be seen that the genotype percentages obtained were 50% BB and 50% Bb.
Therefore, the result of crossing a heterozygous brown-haired dog with a brown-haired homozygous dominant dog, the percentage of possible genotypes is 50% pure dominant and 50% heterozygous.
From these results, it can also be seen that the percentage of phenotypes obtained is 100% brown.
Learn More About Possible Genotypes at: brainly.com/question/14675509
#SPJ4
