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Alina [70]
3 years ago
15

Evaluate the expression 48 ÷ n when n=6?

Mathematics
2 answers:
harkovskaia [24]3 years ago
8 0
Since it is evaluate you don't put an equal sign and you just simplify the problem. Start by plugging in 6 for n and then simplify.
48/6 is 8
Serga [27]3 years ago
3 0
48 divided by n when its 6 is= 8

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Triangles ABC and DEF are similar. AB = 15 cm, BC = 18 cm, and EF = 6 cm. What is DE? A. 4 cm B. 5 cm C. 6 cm D. 7 cm
skad [1K]
ΔABC is similar to ΔDEF
Try to pair up all the similar sides.
AB = 15 cm
DE = ? cm

BC = 18 cm
EF = 6 cm

Now all you have to do is find out how the triangles are similar.
18/6 = 3
This means that triangle ABC is 3 times bigger than DEF.
15/3 = 5

So the answer is:
B. 5 cm
7 0
3 years ago
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Convert the following to mixed numbers
Aleksandr-060686 [28]
a. \\
\frac{13}{12}=\frac{12}{12}+\frac{1}{12}=\boxed{1 \frac{1}{12}} \\ \\
b. \\
\frac{20}{3}=\frac{18}{3}+\frac{2}{3}=\boxed{6 \frac{2}{3}} \\ \\
c. \\
\frac{9}{4}=\frac{8}{4}+\frac{1}{4}=\boxed{2\frac{1}{4}} \\ \\
d. \\
\frac{19}{5}=\frac{15}{5}+\frac{4}{5}=\boxed{3 \frac{4}{5}} \\ \\
e. \\
\frac{28}{6}=\frac{14}{3}=\frac{12}{3}+\frac{2}{3}=\boxed{4 \frac{2}{3}}
6 0
3 years ago
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Given the point (3, 4), which of the following shows that sinxcscx = 1?
yawa3891 [41]
\bf sin(\theta)=\cfrac{opposite}{hypotenuse}\qquad csc(\theta)=\cfrac{hypotenuse}{opposite}\\\\
-------------------------------\\\\
\begin{array}{clclll}
3&,&4\\
\uparrow &&\uparrow \\
x&&y\\
a&&b\\
adjacent&&opposite\\
side&&side
\end{array}\qquad 
\begin{array}{llll}
\textit{using the pythagorean theorem}
\\\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}
\end{array}
\\\\\\
hypotenuse\implies  c=\sqrt{3^2+4^2}\implies c=\sqrt{25}\implies \boxed{c=5}\\\\
-------------------------------\\\\

\bf sin(x)=\cfrac{4}{5}\qquad csc(x)=\cfrac{5}{4}\implies sin(x)csc(x)\implies \cfrac{4}{5}\cdot \cfrac{5}{4}\implies 1
8 0
3 years ago
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Use Newton's method with initial approximation x1 = 1 to find x2, the second approximation to the root of the equation x4 − x −
drek231 [11]

Answer:

x_{2} = 0.0000

Step-by-step explanation:

The formula for the Newton's method is:

x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}

Where f' (x_{i}) is the first derivative of the function evaluated in x_{i}.

x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}

Lastly, the value of x_{2} is determined by replacing x_{1} with its numerical value:

x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}

x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}

x_{2} = 0.0000

8 0
3 years ago
Solve for x i need help pls
MAVERICK [17]

Answer:

I have no clue I'm sorry:(

5 0
3 years ago
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