Answer:
$0.63
Step-by-step explanation:
SOLUTION
From the given data the mean is 62 and standard deviation is 4
It is required to find the probability that a data value is between 57 and 62
That is:

The z scores is calculated using:

Using the x values it follows:

Also,

Thus the required probability is:
![P(-1.25The proability is:[tex]P(-1.25This can be expressed as percentage as:[tex]P(-1.25\lt z\lt0.75)=66.8\%](https://tex.z-dn.net/?f=P%28-1.25The%20proability%20is%3A%5Btex%5DP%28-1.25This%20can%20be%20expressed%20as%20percentage%20as%3A%5Btex%5DP%28-1.25%5Clt%20z%5Clt0.75%29%3D66.8%5C%25)
Therefore the correct option is C
Answer:
The answer is the last one:
4 , 10 , 18 , (k + 1)² + 3(k + 1) and k² + 5k + 4
Step-by-step explanation:
∵ 2 is a factor of n² + 3n
∵ n = 1 ⇒ ∴ (1)² + 3(1) = 1 + 3 = 4 ⇒ 2 is a factor of 4
∵ n = 2 ⇒ ∴ (2)² + 3(2) = 4 + 6 = 10 ⇒ 2 is a factor of 10
∵ n = 3 ⇒ ∴ (3)² + 3(3) = 9 + 9 = 18 ⇒ 2 is a factor of 18
∵ n = k + 1 ⇒ ∴ (k + 1)² + 3(k + 1) ⇒ before the simplify
∵ n = k + 1 ⇒ ∴ k² + 2k + 1 + 3k + 3 = k² + 5k + 4 ⇒ after simplify
Answer:
{1, 5, 25, 125, 625}
Step-by-step explanation:
The smallest positive integers that meet the requirement will be ...
5^0 = 1
5^1 = 5
5^2 = 25
5^3 = 125
5^4 = 625
As a set, these numbers are {1, 5, 25, 125, 625}.
This is the answer, hope this helps you