Sin2(x) +cos(x)=1
from the relation: (sin2(x) +cos2(x) =1 )
so , sin2(x)=1-cos2(x)
by subs. in the main eqn.
1-cos2(x) + cos(x) =1
by simplify the eqn.
cos(x) -cos2(x)=0
take cos(x) as a common factor
cos(x)* (1-cos(x))=0
then cos(x)=0 && cos(x)=1
cos(x)=0 if x= pi/2
& cos(x) = 1 if x = 0 , 2*pi
so the solution is x= {0,pi/2 , 2*pi}
1) to this case you must match both equations
3x+2 = 2x-3 ⇒3x-2x = -3-2⇒x= -5
now the value of x substitute it in the any of two equations, y = 3(-5)+2 = -13
and the other equation is the same value
y = 2(-5)-3 = -13
the point is ( -5,-13)
Answer:
8/5
Step-by-step explanation:
We can use the formula for finding slope for this: 
The answer would be 8/5
Answer:
b) y = f(x - 7) - 3
Step-by-step explanation:
it adds if its goes to the right and subtracts if it goes to the left
And when it goes down then it will also decrease in number.
that is why b) y = f(x - 7) - 3 is the correct answer to put
Answer:
There are 60 monkeys in the Zoo
Step-by-step explanation:
In this question, we are asked to calculate the number of monkeys in a Zoo given some information to use.
Let’s have the total number of monkeys be m.
60% are going monkeys. This means number of young monkeys is 0.6m.
The number of baby and old monkeys is obviously 0.4m.
Ratio of baby to old monkeys is 3:1. This means if we splitter 0.4m into 4, number of baby monkeys is 0.3m while number of old monkeys is 0.1m
Now, subtracting the number of baby monkeys from young monkeys give a total of 18 monkeys.
Let’s project this mathematically;
This means ;
0.6m - 0.3m = 18
0.3m = 18
m = 18/0.3
m = 60
There are 60 monkeys in the zoo
