Answer:
Teachers to Students: 1:9, 1 to 19, 1/19
Students to teachers: 19:1, 19 to 1, 19/1
(If this is wrong the answers might be different for you but this is what I got an I was right)
Answer:
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Step-by-step explanation:
In order to find the maxima or minima of a function, we have to take the first derivative and then put it equal to zero to find the critical values.
Given function is:

Taking first derivative

Now the first derivative has to be put equal to zero to find the critical value

The function has only one critical value which is 5.
Taking 2nd derivative


As the value of 2nd derivative is positive for the critical value 5, this means that the function has a minimum value at x = 5
The value can be found out by putting x=5 in the function

Hence,
<u>The function y = x 2 - 10x + 31 has a minimum value of 6</u>
Hence,
Option B. minimum is correct for the first blank
Option C. 6 is correct for second blank.
Simplifying this, we get:
(x+4)(x-4) = 0
Now, to get 0, we can replace x for one of these things to make 0, so:
x can either be 4, or -4
Answer:
5
Step-by-step explanation:
2x + 5 = 10
you minus the 5
2x = 5
you divide both sides by 2
x = 5
Answer:
x = 2, y = -1.
Step-by-step explanation:
2x - 5y = 9
3x + 4y = 2
Multiply first equation by -3 and the second by 2:
-6x + 15y = -27
6x + 8y = 4 Adding the 2 equations:
23y = -23
y = -1.
Now substitute this value for y in the first equation:
2x - 5(-1) = 9
2x = 9 +5(-1)
2x = 9 - 5
2x = 4
x = 2.