15a-25=35
3.333
Leah needs to buy some apples from the grocery store. She places fifteen apples in her cart and proceeds to the checkout. Lucky for her, there happens to be a discount on apples for the day. She saves $25 on her purchase. The total money she ends up spending was only $35 (excluding tax). How much did each apple cost?
2x + y = 10
5x - y = 18
7x = 28
x = 4
2(4) + y = 10
8 + y = 10
y = 2
(4,2)
Answer:
I think the answer is D. (2,6,8) because if the ones on the right are y - coordinates in the Function then it should be correct. If not sorry
(Range is y - coordinate)
(Domain is x - coordinate)
Answer:
Step-by-step explanation:
Hello!
So you have a new type of shoe that lasts presumably longer than the ones that are on the market. So your study variable is:
X: "Lifetime of one shoe pair of the new model"
Applying CLT:
X[bar]≈N(μ;σ²/n)
Known values:
n= 30 shoe pairs
x[bar]: 17 months
S= 5.5 months
Since you have to prove whether the new shoes last more or less than the old ones your statistical hypothesis are:
H₀:μ=15
H₁:μ≠15
The significance level for the test is given: α: 0.05
Your critical region will be two-tailed:
![Z_{\alpha /2} = Z_{0.025}= -1.96](https://tex.z-dn.net/?f=Z_%7B%5Calpha%20%2F2%7D%20%3D%20Z_%7B0.025%7D%3D%20-1.96)
![Z_{1-\alpha /2} = Z_{0.975}= 1.96](https://tex.z-dn.net/?f=Z_%7B1-%5Calpha%20%2F2%7D%20%3D%20Z_%7B0.975%7D%3D%201.96)
So you'll reject the null Hypothesis if your calculated value is ≤-1.96 or if it is ≥1.96
Now you calculate your observed Z-value
Z=<u>x[bar]-μ</u> ⇒ Z=<u> 17-15 </u> = 1.99
σ/√n 5.5/√30
Since this value is greater than the right critical value, i.e. Zobs(1.99)>1.96 you reject the null Hypothesis. So the average durability of the new shoe model is different than 15 months.
I hope you have a SUPER day!
Answer:
Unable to tell you
Step-by-step explanation:
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