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bogdanovich [222]

2 years ago

15

I need help with this someone please

1 answer:

Alex2 years ago

7 0

3/1 is your slope for that

You might be interested in

What is the quotient and the remainder for <br> 52 divided by 8

Marianna [84]

52/8 = 6
6*8 = 48
52-48 = 4

So 52 = 6*8+4

The quotient is 6, the remainder is 4.

5 0

3 years ago

pentagon [3]

Answer:

2<x<3

Step-by-step explanation:

4x-4<8 AND 9x+5>23

Solve the first inequality

4x-4<8

Add 4 to each side

4x-4+4 <8+4

4x<12

Divide by 4

4x/4 <12/4

x <3

Solve the second inequality

9x+5>23

Subtract 5 from each side

9x+5-5>23-5

9x >18

Divide by 9

9x/9>18/9

x>2

Put together

x<3 and x>2

2<x<3

3 0

3 years ago

Write an expression for the perimeter of the triangle shown below

Luba_88 [7]

Answer:

P = 5.5x + 9

Step-by-step explanation:

P = 5x + (0.3x + 24) + (0.2x - 15)

reduced

P = 5.5x + 9

7 0

3 years ago

Read 2 more answers

Please actually help me. ill give brainliest if you explain your answer.

meriva

Answer:

subtract 11 from both sides

Step-by-step explanation:

-3x+11=44

-3x=33

x=-11

4 0

3 years ago

Read 2 more answers

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

6 0

3 years ago

Read 2 more answers