Which expression is equivalent? Please see pictures attached!

Lesechka [4]

2s + s = 36
3s = 36
s = 36/3
s = 12

7 0

3 years ago

What are the vertex and x-intercepts of the graph of y = (x + 4)(x + 2)? Select one answer for the vertex and one for the x-inte

lora16 [44]

Answer: Vertex (-3, 1) and x-intercept (-4, 0), (-2, 0)

4 0

3 years ago

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If a = b, then a - c = b - c. This is the ___________________ property of equality.

Fantom [35]

Answer:

communitive

Step-by-step explanation:

7 0

3 years ago

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A lawyer has found 60 investors for a limited partnership to purchase an inner-city apartment building, with each contributing e

Zinaida [17]

Answer:

39 investors contributed $6,000, and 21 investors contributed $12,000.

Step-by-step explanation:

Let's say that x investors contributed $6,000, and y investors contributed $12,000.

x + y = 60

6,000x + 12,000y = 486,000

x + 2y = 81

x + y = 60

y = 21

x + 21 = 60

x = 39

So, 39 investors contributed $6,000, and 21 investors contributed $12,000.

Hope this helps!

5 0

3 years ago

PLEASE HELP! Im not very good at math

marysya [2.9K]

Answer:

The answer provided is incorrect, the mistake is in the division between the monomials $x^{\frac{6}{5}}$ and $x^{\frac{2}{5}}$ that is equal to $x^{\frac{4}{5}$ not $x^3$ , because we must mantain the same base "x" and subtract the expoents that are $\frac{6}{5} - \frac{2}{5} = \frac{4}{5}$ .

Step-by-step explanation:

In order to simplify that question we need to multiply, divide and power monomials with the same base "x". When we multiply monomias with the same base we sum the expoents, to divide we subtract the expoents and to power them we multiply the expoents. Therefore to simplify the equations we must do:

$(\frac{x^{\frac{2}{5}}*x^{\frac{4}{5}}}{x^{\frac{2}{5}}})^\frac{1}{2}\\(\frac{x^{\frac{6}{5}}}{x^{\frac{2}{5}}})^\frac{1}{2}\\(x^{\frac{4}{5}})^\frac{1}{2}\\x^{\frac{4}{10}}\\x^{\frac{2}{5}}$

The answer provided is incorrect, the mistake is in the division between the monomials $x^{\frac{6}{5}}$ and $x^{\frac{2}{5}}$ that is equal to $x^{\frac{4}{5}$ not $x^3$ , because we must mantain the same base "x" and subtract the expoents that are $\frac{6}{5} - \frac{2}{5} = \frac{4}{5}$ .

6 0

3 years ago

Read 2 more answers