(a)
Q1, the first quartile, 25th percentile, is greater than or equal to 1/4 of the points. It's in the first bar so we can estimate Q1=5. In reality the bar includes values from 0 to 9 or 10 (not clear which) and has around 37% of the points so we might estimate Q1 a bit higher as it's 2/3 of the points, say Q1=7.
The median is bigger than half the points. First bar is 37%, next is 22%, so its about halfway in the second bar, median=15
Third bar is 11%, so 70% so far. Four bar is 5%, so we're at the right end of the fourth bar for Q3, the third quartile, 75th percentile, say Q3=40
b
When the data is heavily skewed left like it is here, the median tends to be lower than the mean. The 5% of the data from 80 to 120 averages around 100 so adds 5 to the mean, and 8% of the data from the 60 to 80 adds another 5.6, 15% of the data from 40 to 60 adds about 7.5, plus the rest, so the mean is gonna be way bigger than the median of around 15.
Yz =5
Xz= 7
Hope this helps!!!
Answer:
(3,-3)
Step-by-step explanation:
First you divide 2 out of the first equation and it turns into 5x+y=12.
Then you write one on top of the other so you can add them. It looks like:
5x + y = 12
-5x + y = -18
Then you add them together and the 5x's cancel each other out and you are left with 2y = -6
So then you divide both sides by 2 and get y = -3
Then you plug -3 into the second equation because it is simpler and get -5x - 3 = -18
So then you add three to both sides and get -5x = -15
And finally you divide both sides by -5 and get x=3
Answer:
2.63340641 × 10109 m13 / s13
S(r) = 2pi*r*h + 2pi*r^2
S ' (r) = 2pi*h + 2*2*pi*r .... differentiate with respect to r
S ' (r) = 2pi*h + 4pi*r
S ' (3) = 2pi*h + 4pi*3 ... plug in r = 3
S ' (3) = 2pi*h + 12pi
S ' (3) = 2pi*2 + 12pi .... plug in h = 2
S ' (3) = 4pi + 12pi
S ' (3) = 16pi
---------------
Answer: D) 16pi
