it is only half because it is a line the middle
I'm guessing the last value you have down there that got cut off was the one we want. We need to set up the general form of the absolute value equation and then solve it for a:
![y=a[x-h]+k](https://tex.z-dn.net/?f=y%3Da%5Bx-h%5D%2Bk)
. I have no absolute value symbols so I just used brackets. We have a vertex (h, k) of (0, 0) and I picked a point on the graph to use as my x and y coordinates (4, 3). Let's fill in the equation now:
![0=a[0-4]+3](https://tex.z-dn.net/?f=0%3Da%5B0-4%5D%2B3)
. We will subtract 3 from both sides leaving -3 = a[-4]. The absolute value of -4 is 4 so now we have -3 = 4a. Divide by 4 to solve for a.

. So our equation is
Cos 105 will also be -0.26
csc 105 = 1.03
Answer:
1 AND 4/19
Step-by-step explanation:
2/3=3/5
lcm=15
10/15+9/15=19/15= 1 AND 4/19
The point R has coordinates (-5,-5) and the image point R' has coordinates (2,-7).
If
- -5+a=2, then a=2-(-5)=2+5=7;
- -5+b=-7, then b=-7-(-5)=-7+5=-2.
Thus, the translation rule is
(x,y)→(x+7,y-2)
or 
If point U has coordinates (-5,1), then its image U' has coordinates (-5+7,1-2) that is (2,-1).
Answer: correct choice is B