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2 years ago

12

john is running in a race. the race is 25 miles long. after two hours, john has run 7 miles. how many miles, m does john have le

ft to run?

1 answer:

Gre4nikov [31]2 years ago

8 0

John would have to run 18 more miles to finish the race.

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How do I solve system of equations substitution method??!!?!???

adelina 88 [10]

For example:

x+2y=7
6x+7y=2
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x=7-2y *
6*(7-2y)+7y=2 **

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42-12y+7y=2
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x=7-2y
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8 0

2 years ago

What is 18 times 40 to the 9th power

Rzqust [24]

I believe thugs is it
4.718592e+15

3 0

2 years ago

Read 2 more answers

Let Q(x, y) be the predicate "If x < y then x2 < y2," with domain for both x and y being R, the set of all real numbers.

Levart [38]

Answer:

a) Q(-2,1) is false

b) Q(-5,2) is false

c)Q(3,8) is true

d)Q(9,10) is true

Step-by-step explanation:

Given data is $Q(x,y)$ is predicate that $x$ then $x^{2}$ . where $x,y$ are rational numbers.

a)

when $x=-2, y=1$

Here $-2$ that is $x$ satisfied. Then

$(-2)^{2}$

$4$ this is wrong. since $4>1$

That is $x^{2}$ $>y^{2}$ Thus $Q(x,y)$ $=Q(-2,1)$ is false.

b)

Assume $Q(x,y)=Q(-5,2)$ .

That is $x=-5, y=2$

Here $-5$ that is $x$ this condition is satisfied.

Then

$(-5)^{2}$

$25$ this is not true. since $25>4$ .

This is similar to the truth value of part (a).

Since in both $x$ satisfied and $x^{2} >y^{2}$ for both the points.

c)

if $Q(x,y)=Q(3,8)$ that is $x=3$ and $y=8$

Here $3$ this satisfies the condition $x$ .

Then $3^{2}$

$9$ This also satisfies the condition $x^{2}$ .

Hence $Q(3,8)$ exists and it is true.

d)

Assume $Q(x,y)=Q(9,10)$

Here $9$ satisfies the condition $x$

Then $9^{2}$

$81$ satisfies the condition $x^{2}$ .

Thus, $Q(9,10)$ point exists and it is true. This satisfies the same values as in part (c)

6 0

2 years ago

The ones circled please put the answers and what the problem is ok? and thank y'all for the support

Lady_Fox [76]

7) 2-3=-1 9) 6-9=-3
11) -3-4=-7 13) -7-6=-13
15)-3-9=-12 17) 6-(-2)=8
19)3-(-5)=8 21) 5-(-8)=13
23)-2-(-1)=-1 25) -10-(-4)=-6
27)-6-(-5)=-1 29) -8-(-6)=-2
31)5-(-3)=8 33) 7-10=-3
35)-2-5=-7 37) -9-(-4)=-5

5 0

2 years ago

-(-6x - 5) = 4(5x + 3)

Lina20 [59]

Answer:

$\large\boxed{B)\ -\dfrac{1}{2}}$

Step-by-step explanation:

$-(-6x-5)=4(5x+3)\qquad\text{use the distributive property}\\\\-(-6x)-(-5)=(4)(5x)+(4)(3)\\\\6x+5=20x+12\qquad\text{subtrac 5 from both sides}\\\\6x=20x+7\qquad\text{subtract 20x from both sides}\\\\-14x=7\qquad\text{divide both sides by (-14)}\\\\x=-\dfrac{7}{14}\\\\x=-\dfrac{1}{2}$

8 0

2 years ago