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WARRIOR [948]
3 years ago
9

(3x – 70) (3y+40) 120 x

Mathematics
2 answers:
enyata [817]3 years ago
4 0

Answer:

3x-70

Step-by-step explanation:

(3y+40 ) 120x is the answer of that question answer

Lelu [443]3 years ago
4 0

120x(3x-70)(3y+40)=
360x 2nd power -8400x)(3y+40)=
1080x 2nd power y+14400x 2nd power-25200xy-336000x
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A grab bag contains 3 football cards and 7 basketball cards. An experiment consists of taking one card out of the bag, replacing
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Step-by-step explanation:

Sorry can't help

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3 years ago
Twice the difference of a number and 2 is 8
DedPeter [7]

Answer:

2x-2=8

Step-by-step explanation:

2x-2=8

2x=8+2

2×=10

2×÷2×=10÷2

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4 years ago
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3 years ago
A parabola is graphed such that the axis of symmetry is x = 3. One of the x-intercepts is (5, 0). What is the other x-intercept?
Stells [14]

The axis of symmetry is the fold line that splits the parabola down the middle.

Now, since a parabola is symmetrical, every point, except the vertex, will have a mirror image of another point if we folded the parabola over the axis of symmetry.

So if we know the axis of symmetry is x = 3 and one of our points

has the coordinates (5, 0), the other point will have the coordinates (3, 0).

The axis of symmetry is always halfway between the x-intercepts.

6 0
3 years ago
A machine is designed to fill 16-ounce bottles of shampoo. When the machine is working properly, the amount poured into the bott
Andreyy89

Answer:

(15.8495,16.2505)  

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 16.05 ounces

Standard Deviation, σ = 0.2005 ounces

We are given that the distribution of amount poured into the bottles is a bell shaped distribution that is a normal distribution.

Empirical rule:

  • It states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ).
  1. It shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

Confidence interval:

\mu \pm 2\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

16.05 \pm 2(\frac{0.2005}{\sqrt{4}} ) = 16.05 \pm 0.2005 = (15.8495,16.2505)

4 0
3 years ago
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