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Alika [10]
3 years ago
11

The red graph (1) is the graph of f(x) = log(x). Describe the transformation of the blue function (2) and write the equation of

the graph.

Mathematics
1 answer:
Nataly_w [17]3 years ago
8 0

Answer:

first of all, the graphs are so poorly plotted,even kn computer...

anyways,

since the blue one ending at x=5 on the x axis,

while actual log ends at x=0 this means

X=x-5

and since, log1=0 but it's 5 in blue graph,

the graph is moved up by 5

hence,

y=5+log(x-5)

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Plz Help. write as polynomial<br><br><br><br><br>-a²(3a-5)+4a(a²-a)​
Genrish500 [490]

Answer:

a^3 + a^2

Step-by-step explanation:

Distribute the term left of each set of parentheses, then combine like terms.

-a²(3a - 5) + 4a(a² - a)​ =

= -3a^3 + 5a^2 + 4a^3 - 4a^2

= a^3 + a^2

3 0
3 years ago
Which of the following functions is graphed below?
Elza [17]

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5 0
3 years ago
Find the area of the region which is inside the polar curve r=5sin(θ) but outside r=4. Round your answer to four decimal places
natka813 [3]

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be 3.75 square units.

<h3>What is an area bounded by the curve?</h3>

When the two curves intersect then they bound the region is known as the area bounded by the curve.

The area of the region which is inside the polar curve r = 5 sinθ but outside r = 4 will be

Then the intersection point will be given as

\rm 5 \sin \theta  = 4\\\\\theta = 0.927 , 2.214

Then by the integration, we have

\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214}[ (5 \sin \theta)^2 - 4^2] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [25\sin ^2 \theta - 16] d\theta \\\\\\\rightarrow \dfrac{1}{2} \times \int _{0.927}^{2.214} [ \dfrac{25}{2}(1 - \cos 2\theta ) - 16] d\theta \\

\rightarrow \dfrac{1}{2} [\dfrac{25 \theta }{5} - \dfrac{25 \cos 2\theta }{2} - 16\theta]_{0.927}^{2.214} \\\\\\\rightarrow \dfrac{1}{2} [\dfrac{25(2.214 - 0.927) }{5} - \dfrac{25 (\cos 2\times 2.214 - \cos 2\times 0.927) }{2} - 16(2.214 - 0.927]\\

On solving, we have

\rightarrow \dfrac{1}{2} \times 7.499\\\\\rightarrow 3.75

Thus, the area of the region is 3.75 square units.

More about the area bounded by the curve link is given below.

brainly.com/question/24563834

#SPJ4

5 0
2 years ago
3x2=7 5x4=23 7x6=47 9x8=79 10x9=?
Mashcka [7]
(a\times b) = (a\times b) +(b -1) = c \\  \\ 3 \times 2 = (3\times 2) +(2-1) = 6 +1=7 \\  \\ 5 \times 4 = (5\times 4) +(4-1) = 20 +3=23 \\  \\ 7 \times 6 = (7\times 6) +(6-1) = 42 +5=47 \\  \\ 9 \times 8= (9\times 8) +(8-1) = 72 +7=79 \\  \\  \\  \\ 10 \times 9 = (10\times 9) +(9-1) = 90 +8=\boxed {\bf{98}}\\\sf {10\times 9 = \boxed{\bf {98}}}
3 0
3 years ago
On April 1, Preston McCord deposited $1,400 in a savings account that pays annual interest of 3.2%
lesya692 [45]

Answer:

After 6 months, the interest generated by the investment would be $21.10.

Step-by-step explanation:

To determine the interest that Preston McCord could earn by investing $ 1,400 in an account that pays 3.2% annual interest compounded monthly, leaving said money invested for a period of 6 months, it is necessary to perform the following calculation:

X = 1,400 x (1 + 0.032 / 6) ^ 0.5x6

X = 1,421.10

1421.10 - 1400 = 21.10

Thus, after 6 months, the interest generated by the account will be $ 21.10.

4 0
2 years ago
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