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4 years ago

I'd really appreciate it if anyone could help! :) Giving brainliest.

Mathematics

1 answer:

Naddik [55]4 years ago

4 0

Answer:

Step-by-step explanation:

The easiest way to simplify the expression below is using a property: if we take random non-0 number to the 0 power, we finally get 1, so $a^0=1$

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What is the image of -1 - 5 after a dilation by a scale factor of 5 centered at the origin

amm1812

the Given data

*The given point is (-1, -5)

*The given scale factor is 5

The image of -1 - 5 after dilation by a scale factor of 5 centered at the origin is given as

$(-1,-5)=(-1\times5,-5\times5)=(-5,-25)$

Thus, the image after dilation by a scale factor of 5 centered at origin is (-5, -25)

6 0

2 years ago

What is the expression that means the same as 7 less than the square of a number? A. 7-2x B. 7-2× C. 7-x2 D. x2-7

damaskus [11]

Answer d is correct!!!!!

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3 years ago

Read 2 more answers

What is ⅓ divided by ¼? Use the model if needed. Answer should be in simplest form. Explain your answer

Misha Larkins [42]

Answer:

The answer to the expression in simplest form is:

$\frac{\frac{1}{3}}{\frac{1}{4}}=\frac{4}{3}$

Step-by-step explanation:

Given the function

$\frac{\frac{1}{3}}{\frac{1}{4}}$

solving to get the simplest form

$\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c}$

$\frac{\frac{1}{3}}{\frac{1}{4}}=\frac{1\cdot \:4}{3\cdot \:1}$

$\mathrm{Apply\:rule}\:a\cdot 1=a$

$=\frac{4}{3}$

Thus, the answer to the expression in simplest form is:

$\frac{\frac{1}{3}}{\frac{1}{4}}=\frac{4}{3}$

7 0

3 years ago

. Error Analysis Describe and correct the error

aleksklad [387]

Answer:

Step-by-step explanation:

$\sqrt{144} = 12$

the error was in not take the root of the number correctly

the student assumes that the root of 144 was equal to 72

4 0

3 years ago

A company has 2 machines that manufacture widgets. An older machine manufactures 25% defective widgets, while the new machine ma

Bingel [31]

Answer:

73.90%

Step-by-step explanation:

Let Event D=Defective, D' = Non Defective

Let Event N=New Machine, N' = Old Machine

From the given information:

$P(D|N')=0.25\\P(D|N)=0.09\\P(N)=0.7\\P(N')=0.3$

We are required to calculate the probability that a widget was manufactured by the new machine given that it is non defective.

i.e. $P(N|D')$

$P(D'|N')=1-P(D|N')=1-0.25=0.75\\P(D'|N)=1-P(D|N)=1-0.09=0.91$

Using Baye's Law of conditional Probability

$P(N|D')=\dfrac{P(D'|N)P(N)}{P(D'|N)P(N)+P(D'|N')P(N')} \\=\dfrac{0.91*0.7}{0.91*0.7+0.75*0.3}\\ =0.73897\\\approx 0.7390$

Therefore given that a selected widget is non-defective, the probability that it was manufactured by the new machine is 73.9%.

5 0

3 years ago