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emmainna [20.7K]
3 years ago
13

a rectangle of perimeter 100 units has the dimensions shown. Its area is given by the function A = w(50 - w). What is the GREATE

ST area such a rectangle can have? Please explain all steps written, there are parts such as 50W -W^2 and it ends up turning into the next part how?
Mathematics
1 answer:
Anna [14]3 years ago
7 0
If A=w(50-w)

A=50w-w^2

dA/dw=50-2w

d2A/dw2=-2

Since the acceleration is a constant negative, that means that when velocity, dA/dw=0, it is at an absolute maximum for A(w)...

dA/d2=0 only when 50=2w, w=25

So as the case with any rectangle, the perfect square will enclose the greatest area possible with respect to a given amount of material to enclose that area...

So the greatest area occurs when W=L=25 in this case:

A(25)=50w-w^2

Area maximum is thus:

Amax=50(25)-(25)^2=625 u^2
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Find the area of the isosceles triangle formed by points of intersection of the parabolas y=-x2+9 and y=2x2+3 and the origin.
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Answer:

10

Step-by-step explanation:

*I’m assuming that you meant y = 2x^2-3 because that is what my RSM problem was and it was exactly the same problem other than that.* First you want to find the points of intersection of the two parabolas. You can choose to graph them or do any other method. Anyways, the points of intersection are: (2,5) and (-2,5). You now want to add (0,0). So obviously (2,5) to (-2,5) is the base and it is 4 units. The height is 0 to 5 which is 5 units. Do (4*5)/2 and you get 10. Hope this helped you with your RSM and let me know if I assumed correctly.

8 0
3 years ago
WXYZ is an isosceles trapezoid with legs WX and YZ and a base XY. If the length of WX is 6x+5, the length of XY is 10x+4 and the
pav-90 [236]
WX and ZY make up the legs, as illustrated in the diagram.
Since it is an isosceles trapezoid, the legs are congruent; that means
6<em>x</em> + 5 = 8<em>x</em> - 3
When solving this equation, we do not want a variable on both sides.  We will cancel the 6<em>x</em> to avoid negatives:
6<em>x</em> + 5 - 6<em>x</em> = 8<em>x</em> - 3 - 6<em>x</em>
5 = 8<em>x</em> - 3 - 6<em>x</em>
Combine like terms:
5 = 2<em>x</em> - 3
Cancel the 3 by adding:
5 + 3 = 2<em /><em>x</em> - 3 + 3
8 = 2<em>x</em>
Cancel the 2 by dividing:
8/2 = 2<em>x</em>/2
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4 0
4 years ago
Read 2 more answers
Which of the following is a factor of 2x2 - x - 6<br>​
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Step-by-step explanation:

4 0
3 years ago
The account executive of a brokerage firm has recommended that one of her customers consider stock from five aerospace companies
soldier1979 [14.2K]

Answer:

180 ways

Step-by-step explanation:

Aerospace companies (A) = 5

Energy development companies (D) = 3

Electronics companies (E) = 4

Number of aerospace stocks bought (a) = 2

Number of Energy development stocks bought (d) = 2

Number of Electronics stocks bought (e) = 2

The number of ways that the investor can select his six investments from the recommended list is given by the combination of picking two out five aerospace companies, multiplied by picking two out three energy development companies, multiplied by picking two out four electronics companies:

n=\frac{5!}{(5-2)!2!}*\frac{3!}{(3-2)!2!}*\frac{4!}{(4-2)!2!}\\  n=10*3*6\\n=180\ ways

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4 0
3 years ago
Can someone please help with these problems I’m having trouble pls
ololo11 [35]

When the chords intersect inside the circle the sum of the vertical angles and the sum of the referenced arcs are the same.  Since the vertical angles are congruent, each is half the sum of the referenced arcs.

Similarly when the chords intersect outside the circle, the angle is half the <em>difference</em> of the arc measures.

It's the same with a tangent; in that case there's just not a part of the arc that's not counted on the side with the tangent.

OK, that's how.  Let's try some.

1.  x = (88 + 86)/2 = 87

2. x = (150 - 60)/2 = 45

3. The angle is exactly half the subtended arc,

x = 110/2 = 55

4. The referenced arc is 360 - 220 = 140 degrees and x is half, 70.

5.  Outside, half the difference, x = (90-20)/2 = 35

6.  Angle outside, inner arc 6 degrees, vertical angle is 90 degrees.

90 = (x - 6)/2

180 = x - 6

x = 186

7.  There's a special rule for this case but we can treat it as outside, little arc x, big arc 360-x,

60 = (360 - x  - x)/2

120 = 360 - 2x

2x = 240

x = 120

8. Inner arc x, outer arc is 360-140-x = 220-x.  Half the difference is 38,

38 = (220 - x - x)/2

76 = 220 - 2x

2x = 220 - 76

x = (220 - 76)/2 = 72

9.  x is formed by a tangent and a radius, so a right angle, x=90

y is subtended by a 35 degree angle so y=70

10.  Remaining triangle angle is 180 - 62 - 28 = 90.  Arc that subtends it is double, 180.  That means the long side is a diameter.

11.  Remaining triangle angle is 180 - 50 - 70 = 60. x=120, y=100, z=140

12.  Remaining arc 360 - 170 - 90 = 100.  Angles are half.

x=45, y=50, z=85

3 0
3 years ago
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