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yarga [219]
4 years ago
12

Find the product of 2x^2(x + 3)

Mathematics
1 answer:
KengaRu [80]4 years ago
5 0

Answer:

16x

Step-by-step explanation:

2x^2(x+3)

2 times 2 = 4

4x(x+3)

4x + 12x =

16x

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How far apart should she place the two cities on the map
Nat2105 [25]
This is a scaling ratio question. For 1 in is 10 mi so 1:10

Its asking you how long in inches do you have to place those two cities apart. The actual length is 95 mi so the ratio is ?:95

Doing the cross multiply and divide 95*1/10 you get 9.5 in
8 0
3 years ago
Read 2 more answers
You need to cross a canal and want to determine the distance across the opposite side. Since you're able to take measurements on
MariettaO [177]

Answer:

36.7 ft

Step-by-step explanation:

Measurements for the sides of the canal is given as: 40 ft. and 16 ft.

You solve the above question using Pythagoras Theorem

The distance across the canal is calculated as:

√(40² - 16²)

= √(1344)

= 36.66060556 ft

Approximately = 36.7 ft

Therefore, the distance x across the canal = 36.7 ft

8 0
3 years ago
WILL MARK BRAINLIEST!<br> What is the value of g?
pav-90 [236]

Answer:

∠g = 142°

Step-by-step explanation:

∠g = 180 - 38 = 142°

7 0
3 years ago
Does the line whose equation is 4/3 x + 8 pass through the point (9,20)
sergey [27]

Answer: yes

Step-by-step explanation: slope is 4/3 and y intercept is 8

m= Y-20/0-9

4/3= y-20/-9

4/3 x -9 = y-20

-12 = y-20

Y=20-12

Y=8

5 0
3 years ago
Justin has a crate that is 8 feet long 2 feet wide and 3 feet tall decide weather each of the crate sizes described below has th
Nuetrik [128]

Complete question is;

Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall. Decide whether each of the crate sizes described below has the same volume as Justin’s crate.

a. 9 feet long, 1 foot wide, 4 feet tall

b. 8 feet long, 2 feet wide, 2 feet tall

c. 4 feet long, 4 feet wide, 3 feet tall

d. 8 feet long, 3 feet wide, 3 feet tall

e. 6 feet long, 2 feet wide, 4 feet tall Answer:

Options C & E have the same volume as Justin's crate.

Step-by-step explanation:

We are told Justin has a crate that is 8 feet long, 2 feet wide, and 3 feet tall.

Thus, original volume is;

V_o = 8 × 2 × 3 = 48 ft³

A) For a dimension of 9 feet long, 1 foot wide, 4 feet tall , volume is;

V_a = 9 × 1 × 4 = 36 ft³

B) For a dimension of 8 feet long, 2 feet wide, 2 feet tall, volume is;

V_b = 8 × 2 × 2 = 32 ft³

C) For a dimension of 4 feet long, 4 feet wide, 3 feet tall, volume is;

V_c = 4 × 4 × 3 = 48 ft³

D) For a dimension of 8 feet long, 3 feet wide, 3 feet tall, volume is;

V_d = 8 × 3 × 3 = 72 ft³

E) For a dimension of 6 feet long, 2 feet wide, 4 feet tall, volume is;

V_e = 6 × 2 × 4 = 48 ft³

Looking at all the options, the only ones that given a volume equal to Justin's original volume are options C & E.

4 0
3 years ago
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