Answer:
No
Step-by-step explanation:
No, because the perimeter of a rectangle is 2(x+y). Justin added the sides. Then he should have multiplied by 2 but he didn't so Justin is incorrect.
Hope this helps plz mark brainliest :D
Answer:
I say answer number 2
Step-by-step explanation:
You multiply or divide integers just as you do whole numbers, except you must keep track of the signs. To multiply or divide signed integers, always multiply or divide the absolute values and use these rules to determine the sign of the answer.
<span>
When you multiply two integers with the same signs, the result is always positive. Just multiply the absolute values and make the answer positive.</span>
<span>Positive x positive = positive
Negative x negative = positive</span>
<span>When you multiply two integers with different signs, the result is always negative. Just multiply the absolute values and make the answer negative.</span>
<span>Positive x negative = negative
Negative x positive = negative</span>
<span>When you divide two integers with the same sign, the result is always positive. Just divide the absolute values and make the answer positive.</span>
<span>Positive ÷ positive = positive
Negative ÷ negative = positive</span>
<span>When you divide two integers with different signs, the result is always negative. Just divide the absolute values and make the answer negative.</span>
<span>Positive ÷ negative = negative
Negative ÷ positive = negative</span>
Let the lengths of the east and west sides be x and the lengths of the north and south sides be y. the dimensions you want are therefore x and y.
The cost of the east and west fencing is $4*2*x; the cost of the north and south fencing is $2*2*y. We have to put in that "2" because there are 2 sides that run from east to west and 2 sides that run from north to south.
The total cost of all this fencing is $4(2)(x) + $2(2)(y) = $128. Let's reduce this by dividing all three terms by 4: 2x + y = 32.
Now we are to maximize the area of the vegetable patch, subject to the constraint that 2x + y = 32. The formula for area is A = L * W. Solving 2x + y = 32 for y, we get y = -2x + 32.
We can now eliminate y. The area of the patch is (x)(-2x+32) = A. We want to maximize A.
If you're in algebra, find the x-coordinate of the vertex of this quadratic equation. Remember the formula x = -b/(2a)? Once you have calculated this x, subst. your value into the formula for y: y= -2x + 32.
Now multiply together your x and y values to obtain the max area of the patch.
If you're in calculus, differentiate A = x(-2x+32) with respect to x and set the derivative equal to zero. This approach should give you the same x value as before; the corresponding y value will be the same; y=-2x+32.
Multiply x and y together. That'll give you the maximum possible area of the garden patch.
Divide .30 (30%) with 60
60/.30 = 200
200 is your answer
hope this helps
