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4 years ago

Graph the function f(x) = x^2 + 4x - 5 on the coordinate plane

Mathematics

2 answers:

Andreyy894 years ago

7 0

Hello there!

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Hello there, I graphed it on my coordinate plane app, I hope that's what you needed.

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I’ll help with anything else you need!

I hope I helped

@X8lue83rryX

Naya [18.7K]4 years ago

6 0

Answer:

Step 1: a = 1, b = -4

Step 2: x = 2, f(2) = -9

Step 4: (5,0) and (-1,0)

Step 6: f(0) = -5

On the graph the points plotted are (-1,0) , (0,-5) , (2,-9) , and (5,0)

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4 years ago

I am thinking of n consecutive positive integers, the smallest of which is m. What formula represents the largest of these integ

weqwewe [10]

Answer:

$m+n-1$

Step-by-step explanation:

I am thinking of n consecutive positive integers. The smallest of these numbers is m.

So,

$a_1=m$ - the first number,
$a_2=m+1$ - the second number,
$a_3=m+2$ - the third number,
...
$a_n=m+(n-1)=m+n-1$ - the nth number.

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3 years ago

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write a quadratic function in vertex form whose graph has the vertex (1,0) and passes through point (2,-17)

kobusy [5.1K]

Answer:

$\displaystyle f(x) = -17(x-1)^2$

Step-by-step explanation:

We want to write a quadratic function in vertex form whose vertex is (1, 0) and passes through the point (2, -17).

Recall that vertex form is given by:

$\displaystyle f(x) = a(x-h)^2 + k$

Where (h, k) is the vertex and a is the leading coefficient.

Since our vertex is at (1, 0), h = 1 and k = 0:

$\displaystyle f(x) = a(x-1)^2$

It passes through the point (2, -17). Hence, when x = 2, y = -17:

$\displaystyle (-17) = a((2)-1)^2$

Solve for a:

$\displaystyle a = -17$

In conclusion, our quadratic function in vertex form is:

$\displaystyle f(x) = -17(x-1)^2$

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3 years ago

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