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4 years ago

Graph the function f(x) = x^2 + 4x - 5 on the coordinate plane

Mathematics

2 answers:

Andreyy894 years ago

7 0

Hello there!

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Hello there, I graphed it on my coordinate plane app, I hope that's what you needed.

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I’ll help with anything else you need!

I hope I helped

@X8lue83rryX

Naya [18.7K]4 years ago

6 0

Answer:

Step 1: a = 1, b = -4

Step 2: x = 2, f(2) = -9

Step 4: (5,0) and (-1,0)

Step 6: f(0) = -5

On the graph the points plotted are (-1,0) , (0,-5) , (2,-9) , and (5,0)

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damaskus [11]

Kilo means 1000 so 55 times 1000 equals your answer

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4 years ago

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Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

Position of particle A:-

$x(t)=5t-5$

$y(t)=2t-k$

Position of particles B:-

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

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3 years ago

In rectangle QRST, QS= 3x + 7 and RT= 5x - 3. Find the lengths or the diagonals of QRST

Marina CMI [18]

Answer:

The lengths of the diagonals is 22.

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Plug 5 into one of the equations. 3(5)+7=22. 5(5)-3=22

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Answer:

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10 < 3x + 19

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sergiy2304 [10]

Answer:

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