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2 years ago

Easy Question. 4. In photo.

Mathematics

2 answers:

Luden [163]2 years ago

7 0

Use the slope formula:

$\frac{y_2-y_1}{x_2-x_1}$

Plug in the values:

$\frac{2-(-5)}{4-0} = \frac{7}{4}$

So 7/4 is the slope.

djverab [1.8K]2 years ago

5 0

Answer:

Use the slope formula:

\frac{y_2-y_1}{x_2-x_1}

Plug in the values:

\frac{2-(-5)}{4-0} = \frac{7}{4}

So 7/4 is the slope.

Step-by-step explanation:

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Read 2 more answers

Which expression is equivalent to (4g3h2k4)3

RSB [31]

Answer:

d) $8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

$\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$ $= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

Step-by-step explanation:

<u><em>Explanation</em></u>

Given expression

= $\frac{(4g^{3} h^{2}k^{4} )^{3} }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

By using

(ab)ⁿ = aⁿbⁿ

$\frac{a^{m} }{a^{n} } = a^{m-n}$

= $\frac{(4)^{3} g^{9} h^{6}k^{12} ) }{8g^{3}h^{2} } - (h^{5} k^{3} )^{5}$

After simplification , we get

$= 8g^{9}g^{-3} h^{6} h^{-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{9-3}h^{6-2} k^{12} - (h^{5} k^{3} )^{5}$

$= 8g^{6}h^{4} k^{12} - (h^{25} k^{15} )$

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