What is the equation for this and the value of x?

Using the 4 train car strategy for factoring polynomials, what is the green common factor for the 1st two train cars and the gre

koban [17]

The completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)

<h3>How to factor the polynomial?</h3>

The expression is given as:

2x^2 + 4x + 3xy + 6y

Group the expression into two

[2x^2 + 4x] + [3xy + 6y]

Factor out each group

2x(x + 2) + 3y(x + 2)

Factor out x + 2

(2x + 3y)(x + 2)

Hence, the completely factored expression of 2x^2 + 4x + 3xy + 6y is (2x + 3y)(x + 2)

Read more about factored expression at:

brainly.com/question/723406

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7 0

2 years ago

Photos-To-Go printed 2,102 copies of a brochure for a travel agency. The brochure included 5 photos of popular vacation destinat

BigorU [14]

Answer:

All 5 photos will appear once in all the printed brochures

Step-by-step explanation:

Given

$Copies = 2102$

$Photos =5$

Required

The number of times the photo will appear

The interpretation of the question is to determine the number of times the 5 photos will appear in each copy.

From the question, we understand that the photos will appear once in a copy.

By extension, the 5 photos will appear once in other copies.

8 0

3 years ago

a blueprint has the scale of 1/2 inch to 1 foot. on the blueprint, one wall measures 6 inches in height. if h represents the act

Evgen [1.6K]

The expression is h=6x2 which means that h is 12 feet

3 0

3 years ago

Read 2 more answers

HELP! WILL GIVE BRAINLIEST!!!

grin007 [14]

Answer:

The volume of a sphere can be approximated by cylinders. As the number of cylinders approaches infinity the total volume of all the cylinder approaches the actual volume of the sphere.

3 0

3 years ago

The newest invention of the 6.431x staff is a three-sided die. On any roll of this die, the result is 1 with probability 1/2, 2

Gwar [14]

Answer:

<h2>The answer is 0.23(approx).</h2>

Step-by-step explanation:

The given die is a three sided die, hence, there are only three possibilities of getting the outcomes.

We need to find the probability of getting exactly 3s as the result.

From the sequence of 6 independent rolls, 2 rolls can be chosen in $^6C_2 = \frac{6!}{2!\times4!} = \frac{30}{2} = 15$ ways.

The probability of getting two 3 as outcome is $\frac{1}{4} \times\frac{1}{4} = \frac{1}{16}$ .

In the rest of the 4 sequences, will not be any 3 as outcome.

Probability of not getting a outcome rather than 3 is $1 - \frac{1}{4} = \frac{3}{4}$ .

Hence, the required probability is $15\times\frac{1}{16}(\frac{3}{4})^4 = \frac{1215}{4096}$ ≅0.2966 or, 0.23.

4 0

3 years ago