The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
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If you could show a picture of the clocks I could help you
Answer:
36
Step-by-step explanation:
First we need to write out some of the common multiples of 4 and 6.
12, 24, 36
The number 36 is between 25 and 45 so it is our answer
X=3 is the answer I think
Answer:
Fail to reject the null hypothesis.
Step-by-step explanation:
The hypothesis test is conducted for Boston public school. They have used z-value table and the value of test statistics is 1.20. AT the significance level of 0.05, the null hypothesis is accepted. We cannot reject the null hypothesis. The p-value is greater than alpha so there is no evidence to support the claim of Boston Public School.
