PLEASE HELPP!!!! Please find the areas of these shape
1 answer:
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Answer:
15m
Step-by-step explanation:
For every second, the boy walks 1.5 m
So 6 x 1.5 m equals 9 m total
For every second, the girl walks 2m
So 6 x 2 m equals 12 m total
The boy walked North, so it would look like he is walking upward
While the girl walking West looks like she is walking to the left
Finding the distance between them would look like solving a right triangle
We're gonna use the Pythagorean theorem
12² + 9² = distance²
144 + 81 = 225
√225 = 15
Answer:
430 cm2
Step-by-step explanation:
The Lateral Surface Area of it is equal to:
Area of ABCD + Area of A'B'C'D' + Area of ABB'A' + Area of DCC'D' + Area of ADD'A' + Area of BCC'B'
As ABCDA'B'C'D' is a rectangle prism, so that:
+) Area of ABCD = Area of A'B'C'D'
+) Area of ABB'A' = Area of DCC'D'
+) Area of ADD'A' = Area of BCC'B'
=> Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
As ABCDA'B'C'D' is a rectangle prism, so that we have: ABCD, ABB'A', ADD'A' are rectangles.
The formula to calculate the area of rectangle is: Area = Length x Width
We have:
+) Area ABCD = AB x BC =11 x 10 = 110 cm2
+) Area ABB'A = AB x AA' = 11 x 5 = 55 cm2
+) Area ADD'A = AA' x A'D' = 5 x 10 = 50cm2
Total lateral surface area = 2. Area ABCD + 2. Area ABB'A + 2. Area ADD'A
= 2 x 110 + 2 x 55 + 2 x 50 = 430 cm2
