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katen-ka-za [31]
3 years ago
5

I need help with y multiplied by 8 help plz

Mathematics
2 answers:
Alexxandr [17]3 years ago
7 0
Y x 8 = 8y  hope this helps
PolarNik [594]3 years ago
6 0
I REALLY NEED HELP 

Shaul made a password that consists of one letter followed by two digits. The two digits are different. How many posible passwords did Shaul choose from?
You might be interested in
Show your work:
Flura [38]

The distributive property: a(b + c) = ab + ac

127 × 32 = 127 × (30 + 2) = 127 × 30 + 127 × 2 = (130 - 3)  × 30 + (130 - 3) × 2

=(130)(30) - (3)(30) + (130)(2) - (3)(2) = 3900 - 90 + 260 - 6

= 3810 + 254 = 4064


127 × 32 = (130 - 3) × 32 = 130 × 32 - 3 × 32 = 130 × (30 + 2) - 96

= (130)(30) + (130)(2) - 96 = 3900 + 260 - (100 - 4) = 4160 - 100 + 4

= 4060 + 4 = 4064

6 0
3 years ago
HeLp <br> ASAP <br> I suck at math so someone come here and help pleaseeeeee
Sholpan [36]

These are the answers

1. 30%

2. 85%

3. 84%

4. 28%

5. 40%

6. 35%

7. 65%

8. 28%

5 0
3 years ago
Could someone help with #15?
sweet [91]
The total S divided by 8  was 5 more than the if the total S was divided by 10.

So we have S/8 +5 = S/10 and by switching the equation around you get S/10 = S/8+5

The correct answer is B.
8 0
3 years ago
Alan rode his bike for 5 1/5 hours during one week. That same week, Brook rode her bike for 6 1/8 hours. How many more hours did
melomori [17]

Answer:

1-8 =7 duh

Step-by-step explanation:

6 0
3 years ago
The data shows the speed, in miles per hour, of motorists on a stretch of road.
melomori [17]

Answer:

i. 18 miles per hour is an outlier

ii. the outlier decreases the mean speed

Step-by-step explanation:

An outlier in a given data is one of the values that is far greater or lesser compared to others. It affect the mean and standard deviation of a given data significantly.

From the given data, 18 is far too small compared to other values. This is certainly an outlier. This would affect the mean speed by decreasing the value.

An interquartile range is a measure of differences among data by dividing a set of given data into quartile. Increasing the value of the outlier would increase the interquartile range.

k/jkjln/kjln/j

7 0
3 years ago
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