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Mama L [17]
3 years ago
9

What quadrant would negative abscissa and positive ordinate be ?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

It would be quadrant ll.


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Does the following picture represent a linear function?
nekit [7.7K]

Answer: No

Step-by-step explanation: For x 0-2, the y is increasing by +5 every time. However, the moment it hits x=2, it starts decreasing by -5 every time. This means that it does not follow on set pattern (either +5 or -5) and looks more like a ^ than a /.

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Evaluate 2^−1 + 2^−1.
Diano4ka-milaya [45]

Answer:

1

Step-by-step explanation:

2^−1 + 2^−1

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1

4 0
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Can someone pleaseeee help and if you’re correct i’ll give brainliest
Brrunno [24]

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Step-by-step explanation:

8 0
3 years ago
I don’t know what to do with the 3 feet above the ground
Slav-nsk [51]

Answer:

3 seconds

Step-by-step explanation:

You want to set h(t)=3, then take the root such that t≠0. You would have:

3=3+48t−16t^2

Let's solve your equation step-by-step.

3=3+48t−16t2

Step 1: Simplify both sides of the equation.

3=−16t2+48t+3

Step 2: Subtract -16t^2+48t+3 from both sides.

3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)

16t2−48t=0

Step 3: Factor left side of equation.

16t(t−3)=0

Step 4: Set factors equal to 0.

16t=0 or t−3=0

t=0 or t=3

3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.

So the ball was in the air for 3 seconds.

7 0
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Need some help with this question
Aliun [14]

3 1/3, 7-3 2/3=3 1/3, use absolute value

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