3 years ago

What quadrant would negative abscissa and positive ordinate be ?

Mathematics

1 answer:

elena-14-01-66 [18.8K]3 years ago

3 0

It would be quadrant ll.

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Rationalise the denominator by 6 root 7 minus 1

nikklg [1K]

Answer:

Assuming the numerator was 1.

$(6\sqrt{7}+1)/251$

Step-by-step explanation:

Assuming the numerator was 1.

$1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251$

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2 years ago

What is the answer to 2(x-3)-4(x+3)

Lyrx [107]

Step-by-step explanation:

2 (x-3)-4 (x+3)

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3 years ago

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MaRussiya [10]

Answer: 54

Why? You need to put 3 in for x so you get
2(3)^3
3 to the third power is 3*3*3 which equals 27
2(27)
Now you must do 2 times 27 and you get 54

Hope this helps

8 0

3 years ago

What is the value of x in the equation 5(3x + 4) = 23?

Dvinal [7]

Answer:

x = 1/5

Step-by-step explanation:

5(3x + 4) = 23

Distribute

15x+20 = 23

Subtract 20 from each side

15x+20-20 = 23-20

15x = 3

Divide by 15

15x/15 = 3/15

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If the current price of bread dropped by 44 cents, 9 loaves of bread would cost as much as 7 do now. What is the current price o

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The current price is $1.29

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3 years ago