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Mama L [17]
2 years ago
9

What quadrant would negative abscissa and positive ordinate be ?

Mathematics
1 answer:
elena-14-01-66 [18.8K]2 years ago
3 0

It would be quadrant ll.


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Write the number 3,298,076 in word form. Please
tankabanditka [31]

━━━━━━━☆☆━━━━━━━

▹ Answer

3,298,076 is written as three million two hundred ninety eight thousand seventy six.

Hope this helps!

- CloutAnswers ❁

Brainliest is greatly appreciated!

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5 0
3 years ago
Read 2 more answers
Five times a number is the same as 30more than 8 times the number. Find the number
antoniya [11.8K]

Answer:

<h2>7.6</h2>

Step-by-step explanation:

5x=30+8

so x=6+1.6

7.6

<h3>Brainliest please!</h3>
3 0
3 years ago
What is the maximum number of possible solutions for the system shown below?
vekshin1

Answer:

B:  4 solutions

Step-by-step explanation:

Combining the two equations results in 2x² = 52, or x² = 26.

This equation has two solutions:  x = ±√26.

As before, x² = 26.  If we substitute 26 for x² in the 1st equation, we get:

26 - 4y² = 16, or 4y² = 10, or y = ±√5/2.  Again:  two solutions.

If we take x to be +√26, y could be ±√(5/2).

Check:  is ( √26, √(5/2) ) a solution of the system?

Subbing these values into the first equation, we get:

26 - 4(5/2) = 16.  Is this true?

Then 10 = 10.  Yes.

Through three more checks, we find that this system has FOUR solutions.

5 0
2 years ago
On Saturday, the Anderson
Bond [772]

Answer:

\left\{\begin{matrix}2p + 4c = 31.50\\3p + 2c = 33.25\end{matrix}\right.

Step-by-step explanation:

Let's call (as suggested)

p = the cost of one pizza

c = the cost of one cheeseburger

The Anderson Family ordered 2 pizzas and 4 cheeseburgers and paid $31.50, thus:

2p + 4c = 31.50             [1]

Next weekend, they ate at the same restaurant and ordered 3 pizzas and 2 cheeseburgers for $33.25, thus:

3p + 2c = 33.25           [2]

To know the cost of one pizza and one cheeseburger, we need to solve the system of equations defined by [1] and [2]

\left\{\begin{matrix}2p + 4c = 31.50\\3p + 2c = 33.25\end{matrix}\right.

4 0
2 years ago
the area of a Trapezium is 132 cm². Its height is 14 cm the larger parallel side is longer than the other by 16 cm. find the len
charle [14.2K]

1/2 (a+b)h

1/2 (a+16)14=132

8×14=112

14÷2=7

132-112=20

20÷7 =2.857142857

so then a= 2.86 (3sf)

For more questions like that turn it into equation the make a subject of formula

4 0
2 years ago
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