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Mama L [17]
3 years ago
9

What quadrant would negative abscissa and positive ordinate be ?

Mathematics
1 answer:
elena-14-01-66 [18.8K]3 years ago
3 0

It would be quadrant ll.


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Max’s distance : Dave’s distance = 2 km : 5 km = 2:5
Max’s time : Dave’s time = 40 min : 15 min = 40:15 = 8:3
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What’s the square root of 108 a to the 7th power b to the 5th power
MissTica

Answer:

Step-by-step explanation:

Factor all the factors making up the square root.

108: 2*2*3*3*3

a^7: a*a*a*a*a*a*a

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The rule for taking a square root of this is

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3 years ago
If we want to convert 4.00$ to quarters we have to multiply 4 by
Nadusha1986 [10]

Answer:

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Step-by-step explanation:

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Write an indirect proof showing that the diagonals of a parallelogram intersect each other
____ [38]
Its an indirect proof, so 3 steps :-
1) you start with the opposite of wat u need to prove 
2) arrive at a contradiction
3) concludeReport · 29/6/2015261
since you wanto prove 'diagonals of a parallelogram bisect each other', you start wid the opposite of above statement, like below :- step1 : Since we want to prove 'diagonals of a parallelogram bisect each other', lets start by assuming the opposite, that the diagonals of parallelogram dont bisect each other.Report · 29/6/2015261


Since, we assumed that the diagonals dont bisect each other, 
OC≠OA 
OD≠OBReport · 29/6/2015261
Since, OC≠OA, △OAD is not congruent to △OCBReport · 29/6/2015261

∠AOD≅∠BOC as they are vertical angles, 
∠OAD≅∠OCB they are alternate interior angles 
AD≅BC, by definition of parallelogram 
so, by AAS, △OAD is congruent to △OCBReport · 29/6/2015261
But, thats a contradiction as we have previously established that those triangles are congruentReport · 29/6/2015261
step3 :
since we arrived at a contradiction, our assumption is wrong. so, the opposite of our assumption must be correct. so diagonals of parallelogram bisect each other.
4 0
3 years ago
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