I need some help solving this math problem!
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Answer:
There are 336 ways can the teams finish first, second, and third
Step-by-step explanation:
Total no. of teams = 8
First prize is given to one of the 8 teams
So, no. of teams left for second prize = 8-1 =7
Second prize is given to one of the remaining 7 teams
So, no. of teams left for third prize = 7-1=6
So,the teams finish first, second, and third in no. of ways =
The teams finish first, second, and third in no. of ways = 336
Hence there are 336 ways can the teams finish first, second, and third