8,839,469 people* 94% percent of last years population= <span>8,309,101 people after 1 year
</span>8,309,101 people*94% percent of last years population= <span>7,810,555 people after 2 years
</span>7,810,555 people*94% percent of last years population= <span>7,341,922 people after 3 years</span>
Basically you find the data points and fill in the values. For Point J it is (2,4). They want you to do this: (2-4,4-6)...it then becomes (-2,-2).
So
J: (-2,-2)
K: (-1, -4)
I: (-2, -5)
Those are your new points. I hope this helps love! :)
Step-by-step explanation: A line, ray, or line segment (referred to as segment) that is perpendicular to a given segment at its midpoint is called a perpendicular bisector. ... In the diagram above, RS is the perpendicular bisector of PQ, since RS is perpendicular to PQ and PS≅QS. Additionally, since PS≅QS, point S is the midpoint of PQ.
Answer:
25.047 or roughly 25.
Step-by-step explanation:
I solved it wrong the first time then i double check with wolframalpha and got the correct number.
We know that the area of the tile is 18 
and it makes a triangle, we also know the base and height. In this case the base is 2
and the height is also given which is 
.
Area of triangle = 
,
substituting we will end up with 18 =( 2 * ) / 2
Here is the tricky part 
, i totally forgot about that lol.
Simplifying: we will get 18 = 
Now, in order to find the x, we will need to take the log of both sides.
Solving for x we end up getting:
= x
where x = 25.047.
To be honest I deserve a nobel prize not a brainliest lol.
Good question bro, take it easy.
a = amount invested at 5%
b = amount invested at 2%
now, we know the total invested by Mr Wilson was 20000, so whatever "a" and "b" might be, we know that a + b = 20000.
![a + b = 20000\implies b = 20000-a \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{5\% of a}}{\left( \cfrac{5}{100} \right)a}\implies 0.05a~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)a}\implies \begin{array}{llll} 0.02b\\\\ \stackrel{substituting}{0.02(20000-a)} \end{array}](https://tex.z-dn.net/?f=a%20%2B%20b%20%3D%2020000%5Cimplies%20b%20%3D%2020000-a%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cstackrel%7B%5Ctextit%7B5%5C%25%20of%20a%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B5%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%200.05a~%5Chfill%20%5Cstackrel%7B%5Ctextit%7B2%5C%25%20of%20b%7D%7D%7B%5Cleft%28%20%5Ccfrac%7B2%7D%7B100%7D%20%5Cright%29a%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%200.02b%5C%5C%5C%5C%20%5Cstackrel%7Bsubstituting%7D%7B0.02%2820000-a%29%7D%20%5Cend%7Barray%7D)
now, we know the total of earned interest is 550 bucks, so then
