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Colt1911 [192]
3 years ago
11

Find the periodic withdrawals PMT for the annuity given. HINT [See Example 4.] (Assume end-of-period withdrawals and compounding

at the same intervals as withdrawals. Round your answer to the nearest cent.) $100,000 at 6%, paid out monthly for 11 years
Mathematics
1 answer:
Anettt [7]3 years ago
8 0
It depends on if the interest rate of 6% is nominal or not.  The question doesn't specify.  Let's assume that is is a nominal rate, compounded monthly.
Start with 100000 = x * a angle 132 at .5% per month
This becomes 100000 = x * (1-1.005^-132)/.005
Which becomes (100000(.005))/(1 - 1.005^-132) = x
So x is the PMT, which is 1036.70.
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Luba_88 [7]
I believe the correct answer would be 5,1,3 :)
3 0
2 years ago
Read 2 more answers
A customer states that she was shorted in change by receiving only 23 cents change from $3.00
Artemon [7]

Answer:

First, I would check and see if she was correct. If she wasnt, I would simply show her why she was incorrect. If I was to accidently short her, I would give her the money and move on with my day. if she refused to leave after showing her that I gave her the correct amount of money, she would probably call for the manager. I'd get the manager, explain what happened, and the annoying customer would most likely get kicked out of the store.

(P.S: sorry if it was a little confusing lol)

8 0
3 years ago
Assume the mean useful life of a particular light bulb is 2,000 hours and is normally distributed with a standard deviation of 3
Yuri [45]
The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours
4 0
3 years ago
Find two vectors in R2 with Euclidian Norm 1<br> whoseEuclidian inner product with (3,1) is zero.
alina1380 [7]

Answer:

v_1=(\frac{1}{10},-\frac{3}{10})

v_2=(-\frac{1}{10},\frac{3}{10})

Step-by-step explanation:

First we define two generic vectors in our \mathbb{R}^2 space:

  1. v_1 = (x_1,y_1)
  2. v_2 = (x_2,y_2)

By definition we know that Euclidean norm on an 2-dimensional Euclidean space \mathbb{R}^2 is:

\left \| v \right \|= \sqrt{x^2+y^2}

Also we know that the inner product in \mathbb{R}^2 space is defined as:

v_1 \bullet v_2 = (x_1,y_1) \bullet(x_2,y_2)= x_1x_2+y_1y_2

So as first condition we have that both two vectors have Euclidian Norm 1, that is:

\left \| v_1 \right \|= \sqrt{x^2+y^2}=1

and

\left \| v_2 \right \|= \sqrt{x^2+y^2}=1

As second condition we have that:

v_1 \bullet (3,1) = (x_1,y_1) \bullet(3,1)= 3x_1+y_1=0

v_2 \bullet (3,1) = (x_2,y_2) \bullet(3,1)= 3x_2+y_2=0

Which is the same:

y_1=-3x_1\\y_2=-3x_2

Replacing the second condition on the first condition we have:

\sqrt{x_1^2+y_1^2}=1 \\\left | x_1^2+y_1^2 \right |=1 \\\left | x_1^2+(-3x_1)^2 \right |=1 \\\left | x_1^2+9x_1^2 \right |=1 \\\left | 10x_1^2 \right |=1 \\x_1^2= \frac{1}{10}

Since x_1^2= \frac{1}{10} we have two posible solutions, x_1=\frac{1}{10} or x_1=-\frac{1}{10}. If we choose x_1=\frac{1}{10}, we can choose next the other solution for x_2.

Remembering,

y_1=-3x_1\\y_2=-3x_2

The two vectors we are looking for are:

v_1=(\frac{1}{10},-\frac{3}{10})\\v_2=(-\frac{1}{10},\frac{3}{10})

5 0
3 years ago
Which triangle congruence theorem can be used to prove the triangles are congruent
Trava [24]

Answer:

SSS triangle congruence theorem

explanation:

If three sides of one triangle are congruent to three sides of another triangle, then the triangles are congruent.

7 0
2 years ago
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