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fgiga [73]
3 years ago
12

Assume the mean useful life of a particular light bulb is 2,000 hours and is normally distributed with a standard deviation of 3

00 hours. Calculate the useful life of light bulbs within two standard deviations of the mean.
Mathematics
1 answer:
Yuri [45]3 years ago
4 0
The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours
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Using the percentage concept, it is found that 40% of Alberto’s income is used to pay for his rent and groceries.

<h3>What is a percentage?</h3>

The percentage of an amount a over a total amount b is given by a multiplied by 100% and divided by b, that is:

P = \frac{a}{b} \times 100\%

In this problem:

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  • He spends 896 + 384 = $1280 in rent and groceries, hence a = 1280.

Then, the percentage is given by:

P = \frac{1280}{3200} \times 100\% = 40\%

More can be learned about the percentage concept at brainly.com/question/10491646

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What fraction and decimal, in the hundredths is equivalent to 7/100?
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An employee puts 10000 in a retirement account that offers 4% interest. How much will he have in 12 years
steposvetlana [31]

Answer:

14800

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The formula for simple interest (I) in terms of principal (P), rate (R) and time (T) is given as follows;

I = P x R x T / 100         ------------- (i)

Given:

Principal (P) = Initial amount being put into the account = 10000

Rate (R) = The interest rate being offered by the account manager = 4%

Time (T) = Time taken = 12 years

Substitute these values into equation (i) as follows:

I = 10000 x 4 x 12 / 100

I = 4800

Therefore, the initial amount will yield an interest of 4800 for those 12 years.

The total amount the employee will thus have in 12 years will be the sum of the initial amount and the interest. i.e

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Amount = 10000 + 4800

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