Question

Assume the mean useful life of a particular light bulb is 2,000 hours and is normally distributed with a standard deviation of 300 hours. Calculate the useful life of light bulbs within two standard deviations of the mean.

Answer 1

The mean = 2,000
s = Sigma ( standard deviation ) = 300
M - 2 s = 2,000- 2 * 300 = 2,000 - 600 = 1,400
M + 2 s = 2,000 + 2 * 300 = 2,000 + 600 = 2,600
Answer.
Useful life of light bulbs within 2 standard deviations of the mean is:
A ) Between 1,400 and 2,600 hours