Assume the mean useful life of a particular light bulb is 2,000 hours and is normally distributed with a standard deviation of 3
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X = older brother
y = younger brother
Equation 1: x/y = 2/3 ⇒ x = 2y/3
Equation 2: x + 8/y + 8 = 3/4
The age of the older brother is 24.
The age of the youngest brother is 16.
y = younger brother
Equation 1: x/y = 2/3 ⇒ x = 2y/3
Equation 2: x + 8/y + 8 = 3/4
The age of the older brother is 24.
The age of the youngest brother is 16.