Answer:
I'm not really rich but I have a kitsune and a fly and ride potion, also I plan on buying more robux soon
Step-by-step explanation:
It would be 6,000. if you need the work, please
just ask :)
Answer:
A) 0.106
Step-by-step explanation:
8e^3x + 4 = 15
Subtract 4 from each side
8e^3x + 4-4 = 15-4
8e^3x = 11
Divide each side by 8
8/8e^3x = 11/8
e^(3x) = 11/8
Take the natural log of each side
ln(e^(3x)) = ln(11/8)
3x = ln(11/8)
Divide by 3
3x/3 = 1/3 ln(11/8)
x = 1/3 ln(11/8)
x =.106151244
To the nearest thousandth
x = .106
Answer:
x = 20,000
p = $40
If the price increase by $1, the demand will decrease by 1000
Step-by-step explanation:
Given:
x = 160 - p
x = number of Robby costumes demanded in thousands
p = price in dollars.
a. How many costumes can be sold at a price of $140?
x = 160 - p
x = 160 - 140
= 20
x = 20,000
20 thousand costumes can be sold at a price of $140
b. What price should be charged if the demand is 120,000 Robby costumes?
x is in thousand
p is in dollars
x = 160 - p
x + p = 160
120 + p = 160
p = 160-120
= 40
p = $40
c. If the price increases by $1.00, by how much does the demand decrease?
x = 160 - p
= 160 - 141
= 19
x= 19,000
If the price increase by $1, the demand will decrease by 1000
Assuming you are solving for x
do the opposite of PEMDAS. Isolate the x. Because of equal sign, what you do to one side, you do to the other.
x/5 + 9 = 4
x/5 + 9 (-9) = 4 (-9)
x/5 = 4 - 9
x/5 = -5
x/5(5) = -5(5)
x = -5(5)
x = -25
-25 is your answer for x
hope this helps
