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Nadusha1986 [10]
3 years ago
13

If it rained on 3 days out of 20 days on what percent of the days did it rain

Mathematics
2 answers:
RUDIKE [14]3 years ago
5 0
I’m pretty sure it’s 15% but I I can’t be 100% certain I wasn’t very good at math. O.o
Andrei [34K]3 years ago
3 0
It rained on 15% of those days
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8. Patrice and Don buy a home for $92,000. The property tax rate is$39.50 per $1,000 of assessed value. The assessment rate is 4
Kaylis [27]

We start by calculating the assessed value, that is 41% of the price.

The price is $92,000.

Then, the assessed value is:

AV=a\cdot P=\frac{41}{100}\cdot92000=0.41\cdot92000=37720

The property tax rate is $39.50 per $1000 of assessed value, so we can express this rate as:

\text{tax rate}=\frac{39.50}{1000}=0.0395

We then can multiply this rate by the assessed value to calculate the total property tax:

\text{tax}=0.0395\cdot37720=1489.94

NOTE: we could have also multiplied 39.50 by 37.72. The value 37.72 is the thousands of dollars of assessed value. We would have obtained the same result: 39.50*37.72=1489.94.

Answer: the property tax is $1,489.94.

3 0
2 years ago
Please answer this i dont understnad
serg [7]
The answer would be 6fg^3+5f^2g^2+f^3g-7
7 0
4 years ago
Identify this conic section. x 2 + y 2 = 25 line circle ellipse parabola hyperbola
patriot [66]

Answer:

circle

Step-by-step explanation:

The equation

x² + y² = r²

Represents a circle centred at the origin with radius r

x² + y² = 25 ← is in this form and

is a circle centre (0, 0) with r = 5

7 0
4 years ago
Read 2 more answers
For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
Rus_ich [418]

To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

Now \mathrm{Compute\:the\:signs\:of\:the\:factors\:of\:}\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}\\

Signs of x^2+x+3>0

\mathrm{Choosing\:ranges\:that\:satisfy\:the\:required\:condition:}\:\ge \:\:0

x\frac{3}{2} is the required solution of the given inequality.

5 0
4 years ago
Read 2 more answers
If the perimeter of a square is 68 feet, find the approximate length of its diagonal.A. 17 feet B. 24 feet C. 38 feet D.
Elanso [62]

Find the side length:

Side = 68/4 = 17

Now use Pythagorean theorem:

Diagonal = sqrt(17^2 + 17^2)

Diagonal = sqrt(289 + 289)

Diagonal = sqrt(578)

Diagonal = 24 feet

The answer is B. 24 feet

8 0
3 years ago
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