If u can help me and show work plzzz!!!
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Answer:
400 sq. ft.
Step-by-step explanation:
We gotta find the length of a side:
First, we divide 80 by 4, because the perimeter of a square is (4 x side):
80 ft. / 4 = 20 ft.
Second, we doing the normal area of a square equation:
= 400 square ft.
Which leads to out answer of 400 sq. ft.
The image of Triangle ABC have coordinates as
A'(-2,5)
B'(-2,-1)
C'(7,-1)
Step-by-step explanation:
The figure show that Points A(-4,-1),B(-4,-3) and C(-1,-3) forms the Triangle ABC
It is asked to scaled the triangle with scale factor of 3 and centered at P(-5,-4)
For point A(-4,-1) :
Distance of A(-4,-1) from center P(-5,-4) in x-direction is 1 units and y-direction is 3 units
After scale by factor of 3,
Distance of A(-4,-1) from center P(-5,-4) is also multiply by 3
New distance in x-direction is 3 units and 9 units in y-direction from center P(-5,-4)
Therefore, New location A' is ((-5)+3,(-4)+9)=(-2,5)
For point B(-4,-3)
Distance of B(-4,-3) from center P(-5,-4) in x-direction is 1 units and y-direction is 1 units
After scale by factor of 3,
Distance of B(-4,-3) from center P(-5,-4) is also multiply by 3
New distance in x-direction is 3 units and 3 units in y-direction from center P(-5,-4)
Therefore, New location B' is ((-5)+3,(-4)+3)=(-2,-1)
For point C(-1,-3)
Distance of C(-1,-3) from center P(-5,-4) in x-direction is 4 units and y-direction is 1 units
After scale by factor of 1,
Distance of C(-1,-3) from center P(-5,-4) is also multiply by 3
New distance in x-direction is 12 units and 3 units in y-direction from center P(-5,-4)
Therefore, New location C' is ((-5)+12,(-4)+3)=(7,-1)
Therefore, The image of Triangle ABC have coordinates as
A'(-2,5)
B'(-2,-1)
C'(7,-1)
