All categories

3 years ago

Which of the following equations has the same solution as m - (-62) = 45?

1 answer:

4 0

Hi Emmaelizabethmot286t

m - (-62) = 45 is the special equation so I'm a solve it and look for the same answer of the other options, so below is my work on how i got the answer of the special equation.

m + 62 = 45
m = 45 - 62
m = -17

The answer would be choice A) x + 25 = 8 and the x in that equation is -17 and -17 + 25 = 8 and that's true, and i figured out the answer by subtracting 25 from both sides and subtracting 8 - 25 so it can be -17.

You might be interested in

Maria estimates college tuition and fees, room and board, books, and other charges total $10,100. She will receive a scholarship

garri49 [273]

Maria needs to save $187.50 per month in order to attend college.

First, subtract the $1,100 scholarship from the cost of college, or $10,100, to get $9,000. This is the amount that she needs to save after 4 years. Next, since she is saving monthly, we need to know how many monthly periods are in 4 years, so multiply 12 months/year by 4 years to get 48 monthly periods. Finally, divide the total amount needed ($9,000) by the monthly periods (48) to get $187.50. This answer would change if she earned any interest on her savings, and depending on the compounding period, if any, for such interest.

3 0

3 years ago

A die is rolled 20 times. given that three of the rolls came up 1, five came up 2, four came up 3, two came up 4, three came up

Serjik [45]

Solution:

Number of times a die is rolled = 20

1 - 3=A

2 - 5=B

3 - 4=C

4 - 2=D

5 - 3=E

6 - 3=F

Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times

= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes

= 6! × [ 3! × 5! × 4!×2!×3!×3!]

= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]

= 895795200 Ways

8 0

3 years ago

What is the value of x and y?

aksik [14]

Answer:

Any thing u want

Step-by-step explanation:

The value of y is 25 means, in this equation, no matter what value you choose for x, y will always equal 25. So x can be anything you want.

7 0

3 years ago

wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba

umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (W), 4 black (B) and 2 orange (O) balls.

The winning and losing criteria are:

Win $2 for each black ball selected.
Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, ${14\choose 2}=91$ ways.

The distribution of amount won or lost is as follows:

Outcomes: WW WO WB BB BO OO

X: -2 -1 1 4 2 0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, ${8\choose 2}=28$ ways.

The probability of WW is,

$P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077$

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, ${8\choose 1}\times {2\choose 1}=16$ ways.

The probability of WO is,

$P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758$

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, ${8\choose 1}\times {4\choose 1}=32$ ways.

The probability of WB is,

$P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516$

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, ${4\choose 2}=6$ ways.

The probability of BB is,

$P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659$

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, ${4\choose 1}\times {2\choose 1}=8$ ways.

The probability of BO is,

$P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879$

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, ${2\choose 2}=1$ ways.

The probability of OO is,

$P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110$

The probability distribution of X is:

Outcomes: WW WO WB BB BO OO

X: -2 -1 1 4 2 0

P (X): 0.3077 0.1758 0.3516 0.0659 0.0879 0.0110

3 0

4 years ago

A flowerbed surrounds the base of a tree. It’s enclosed by stones to form a circle that measures 25.12 feet. What is the radius

Ymorist [56]

2.83 if rounded. 2.82842712475 would be the actual.

Hope this helped!

5 0

4 years ago