Let's call :
x=the number of downloaded standard version
y= the number of downloaded high-quality version
We have : -the high-quality version was downloaded three times as often as the
standard version => 3x=y
-standard version is 2.8 megabytes .the high-quality version is 4.6
MB.The total size downloaded for the two versions was 4482 MB
=> 2.8x+4.6y=4482
Solve for x,y
x=270 , y=810
F(-4)= 9*3^(-4)=9/(3^4)=1/9
The LCD = 6x^2y^3 ( because LCD of 3 and 6 = 6, LCD of x^2 and x = x^2 and LCD of y and y^3 = y^3)
now divide 3x^2y into the LCD then multiply this by 5 to get the first term in the numerator and do similar process to get second term, so we get:-
5(2y^2) - 4(x)
------------------
6x^2y^3
= 2( 5y^2 - 2x)
-----------------
6x^2y^3
= 5y^2 - 2x
-----------
3x^2y^3
(0,-2)(1,1)
slope = (1+2)/(1-0) = 3
parallel lines have same slope
so answer
<span>C) 3
--------------
C (0,2) if SF = 1/2
so C'(0. 1)
answer
</span><span>C) (0, 1) </span>
Answer:
w=15
Step-by-step explanation: