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Sever21 [200]
4 years ago
6

A 1-g sample of the compound hydrogen chloride was analyzed and found to be 2.74 percent hydrogen and 97.3 percent chlorine. Wha

t percentage of hydrogen is present in a 2-g sample of hydrogen chloride?
Chemistry
1 answer:
inna [77]4 years ago
6 0

Answer:

2.74 percent hydrogen and 97.3 percent chlorine are in 2 g of compound.

The same as initial

Explanation:

HCl → H⁺ + Cl⁻

2.74% H means that in 100 g of compund, 2.74 grams are H

97.3 % Cl means that in 100 g of compound, 97.3 grams are Cl

So how many grams of H and Cl, are in 1 g of compound

100 g ___ 2.74 g are H _____ 97.3 g are Cl

1g _____ 2.74/100 ____ 97.3/100

0.0274 g are H

0.973 g are Cl

In 2 grams we will find

0.0274 g .2 = 0.0548 g of H

0.973 g .2 = 1.946 g of Cl

(grams / total grams) . 100 = %

(0.0548/2 ) .100 = 2.74%

(1.946 /2) .100 = 97.3%

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2Al2O3 → 4Al + 302
Anuta_ua [19.1K]

540g

Explanation:

Given parameters:

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Unknown:

Mass of aluminium = ?

Solution:

To find the mass of the aluminium formed from this reaction, we work from the known to the unknown. The known here is the mass of the aluminium oxide.

Using this mass, find the number of moles in the aluminium and relate it using the balanced equation to that of the unknown aluminium.

From the number of moles, we can easily find the mass of the aluminium.

Solving:

    Balanced equation:

                 2Al₂O₃ → 4Al + 3O₂

Number of moles of Al₂O₃ = \frac{mass}{molar mass}

   Molar mass of Al₂O₃  = 2(27) + 3(16) = 102g/mol

    Number of moles =  \frac{1020}{102} = 10mol

From the balanced equation:

        2 moles of  Al₂O₃ produced 4 moles of Al

        10 moles of Al will produce    \frac{4 x 10}{2} = 20moles of Al

Mass of Al = number of moles of Al x molar mass of Al = 20  x 27 = 540g

Learn more:

Number of moles brainly.com/question/13064292

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