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Papessa [141]
3 years ago
9

What is the 4th term in a geometric sequence for which a1=15 and r=1/3

Mathematics
1 answer:
Hitman42 [59]3 years ago
8 0
Geometric goes liket his
a_n=a_1(r)^{n-1}
given
a1=15
r=1/3
find a4 or 4th term

a_4=15( \frac{1}{3} )^{4-1}
a_4=15( \frac{1}{3} )^{3}
a_4=15 (\frac{1}{27})
a_4=\frac{15}{27}
a_4=\frac{5}{9}
4th term is 5/9
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Answer:

Step-by-step explanation:

When you roll dice, there are 6 possible outcomes.  

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So you have a 5:6 chance of not rolling a 6.

But they're asking you to use the chart.

Based on the chart, you've rolled the die 24+10+8+3+30+15=90 times.

Of those 90 times, you rolled a 6 15 times.

Which means you did not roll a 6 90-15=75 times.

Therefore the probability of not rolling a 6, based on the chart, is 75/90=83%.

Notice that 5/6=83% as well.  So this chart is fairly accurate.

Now for number 2.

Based on the chart, odd numbers appear 24+8+30=52 times out of the 90.

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If James is rolling the cube 250 times, we know odd numbers will show up 58% of the time so, .58*250=144 is how many times we can expect to see an odd number appear.

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Step-by-step explanation:

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