Ken's distance is: d(t)=1.7t
Ken's shadow is:
(14-6)/d(t)=14/s
8/d(t)=14/s
s=14d(t)/8
s=1.75d(t) and using the value for d(t) we have:
s=1.75(1.7t)
s=2.975t and if you want it in terms of d, d=1.7t, t=d/1.7 so
s=2.975(d/1.7)
s=1.75d
Answer:
A Variable
Step-by-step explanation:
Variables are used to mark an unknown value. Common math problems ask you to solve for it.
For example in 5x+23=45, 'x' is the variable.
A constant is a number without a variable.
<em>Brainilest Appreciated. </em>
Factor out cosx: cosx(sinx-2)=0
cosx=0 or sinx-2=0
cosx=0 or sinx=2
the largest value of sinx is 1, sinx will never be 2, so cosx=0, x=π/2 or 3π/2 are the two answers.
Answer:The answer is B
Step-by-step explanation: because mitchells line is traveling steeper than matthews
Answer:
Step-by-step explanation:
If a point (x, y) is translated by 4 units horizontally right and 1 unit upwards, coordinates of the image point will be,
(x, y) → (x + 4. y + 1)
Therefore, vertices of the image triangle ABC will be,
A(2, 2) → A'(2+4, 2+1)
→ A'(6, 3)
B(5, -1) → B'(5+4, -1+1)
→ B'(9, 0)
C(1, -2) → C'(1+4, -2+1)
→ C'(5, -1)
Then reflected across y-axis.
Rule for the reflection across y-axis will be,
(x, y) → (-x, y)
A'(6, 3) → A"(-6, 3)
B'(9, 0) → B"(-9, 0)
C'(5, -1) → C"(-5, -1)
