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Alexandra [31]
3 years ago
7

Write an equation of the line that goes through the point (-5,-6) and is perpendicular to the line y= -1/2x + 1

Mathematics
1 answer:
Oxana [17]3 years ago
3 0
So the (-5,-6) is negative so if you had the q1 q2 q4 q3 box both number will go down then left because it’s negative if it’s positive it’ll go up and then right
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the least common denominator of two fractions is 12. if you add the two denominators, their sum 7. what are the denominators?
Varvara68 [4.7K]
3 and 4

3 x 4 = 12
3 + 4 = 7
8 0
3 years ago
Read 2 more answers
How many solutions does the equation −2y + 2y + 3 = 3 have? One Zero Infinitely many Three
AnnZ [28]

Answer:

Infinitely many solutions.

Step-by-step explanation:

In the equation −2y + 2y + 3 = 3  we see only one variable, and that variable is of the first power.  Ordinarily, we'd say that this equation will have 1 solution.  However, if we combine like terms, we get 0 + 3 = 3, or 0 = 0, which is true for any and all y values.  Infinitely many solutions.

3 0
3 years ago
Read 2 more answers
Verify the identity. 4 csc 2x = 2 csc2x tan x
vlada-n [284]

Step-by-step explanation:

4csc(2x) = 2csc^2(x) tan(x)

We start with Left hand side

We know that csc(x) = 1/ sin(x)

So csc(2x) is replaced by 1/sin(2x)

4 \frac{1}{sin(2x)}

Also we use identity

sin(2x) = 2 sin(x) cos(x)

4 \frac{1}{2sin(x)cos(x)}

4 divide by 2 is 2

Now we multiply top and bottom by sin(x) because we need tan(x) in our answer

2\frac{1*sin(x)}{sin(x)cos(x)*sin(x)}

2\frac{sin(x)}{sin^2(x)cos(x)}

2\frac{1}{sin^2(x)} \frac{sin(x)}{cos(x)}

We know that sinx/ cosx = tan(x)

Also  1/ sin(x)= csc(x)

so it becomes 2csc^2(x) tan(x) , Right hand side

Hence verified



6 0
3 years ago
PLZ help thnx
Pepsi [2]

Answer:

A) $40

B) 40M = P

C)  $3,120

Step-by-step explanation:

Given that at her salon, last week Tammy did 25 manicures and collected $ 1000, to calculate the slope to represent the manicures, write an equation to represent this relation and determine how much would Tammy make if she did 78 manicures in a month the following calculations should be performed:

A)

1000/25 = X

40 = X

Thus, each manicure costs $ 40.

B)

40M = P

C)

78 x 40 = X

3.120 = X

So if she did 78 manicures in a month, Tammy would earn $ 3,120.

8 0
3 years ago
Q and R are not mutually exclusive events. p (q) = 3/5 p(r) = 1/3 and p ( q and r)= 1/5 find P(Q or R).
V125BC [204]
Recall the inclusion/exclusion principle:

\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)-\mathbb P(Q\cap R)

which means

\mathbb P(Q\text{ or }R)=\dfrac35+\dfrac13-\dfrac15=\dfrac{11}{15}
5 0
3 years ago
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