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Nataly [62]
3 years ago
12

Q and R are not mutually exclusive events. p (q) = 3/5 p(r) = 1/3 and p ( q and r)= 1/5 find P(Q or R).

Mathematics
1 answer:
V125BC [204]3 years ago
5 0
Recall the inclusion/exclusion principle:

\mathbb P(Q\cup R)=\mathbb P(Q)+\mathbb P(R)-\mathbb P(Q\cap R)

which means

\mathbb P(Q\text{ or }R)=\dfrac35+\dfrac13-\dfrac15=\dfrac{11}{15}
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