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3 years ago

PLZZZZ NEED HELP!!!!!!

Mathematics

1 answer:

jeka943 years ago

7 0

Notice the 7) 1st sequence, and the 8) second one

$\bf \begin{array}{llll}
term&value\\
-----&-----\\
1&t_1=-2(1)+5\\
2&t_2=-2(2)+5\\
3&t_3=-2(3)+5\\
4&t_4=-2(4)+5\\
5&t_5=-2(5)+5\\
6&t_6=-2(6)+5\\
7&t_7=-2(7)+5\\
8&t_8=-2(8)+5\\
9&t_9=-2(9)+5\\
\end{array}\qquad \qquad 
\begin{array}{llll}
term&value\\
-----&-----\\1&t_1=2(3)^{1-1}\\2&t_2=2(3)^{2-1}\\3&t_3=2(3)^{3-1}\\\end{array}$

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You have the following function:

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$\frac{dM(t)}{dt}=(1.34)^{\frac{t}{6}+4}(\frac{1}{6})ln(1.34)\\\\\frac{dM(t)}{dt}=\frac{ln(1.34)}{6}[(1.43)^{\frac{t}{6}+4}]\\\\\frac{dM(t)}{dt}=\frac{ln(1.34)}{6}M(t)$ (1)

where you have used the following general derivative:

$g(t)=a^{f(t)}\\g'(t)=a^{f(t)}f'(t)ln(a)$

The derivative give you the increase in the mass per day (because t is days). By the expression (1) you can conclude that each day the mass increase a factor of [ln(1.34)/6].

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