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ale4655 [162]
4 years ago
8

The revenue of 200 companies is plotted and found to follow a bell curve. The mean is $815.425 million with a standard deviation

of $22.148 million. Would it be unusual for a randomly selected company to have a revenue between $747.89 and 818.68 million?1) It is impossible for this value to occur with this distribution of data.2) The value is unusual.
3) We do not have enough information to determine if the value is unusual.
4) The value is not unusual.
5) The value is borderline unusual.
Mathematics
1 answer:
True [87]4 years ago
6 0

Answer:

option 4

The value is not unusual.

Step-by-step explanation:

If the probability of revenue between $747.89 and $818.68 million is low i.e. less than 5% then we can say that it would be unusual for a randomly selected company to have a revenue between $747.89 and 818.68 million.

We are given that revenue found to follow a bell curve. Also, we are given that mean=815.425 and standard deviation=22.148.

P(747.89<x<818.68)=?

P((747.89-815.425)/22.148<z<(818.68-815.425)/22.148)=P(-3.05<z<0.15)

P(747.89<x<818.68)=0.4989+.0596=0.5585

Thus, the probability for a randomly selected company to have a revenue between $747.89 and 818.68 million is not low and so the value is not unusual.

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