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inn [45]
4 years ago
15

How should i do this?

Mathematics
1 answer:
liq [111]4 years ago
5 0
The answer is 5/22,
first change the mixed fraction into an I'm proper fraction which will be 22/5
22/5×5/22=1
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First 8 is added to me , then j am multiplied by 6.then 40 is subtracted from me .Finally I am divided by 10. The result is 11.
alexdok [17]
11x10=110
110+40=150
150/6=25
25-8=17
17 is the number.
4 0
3 years ago
The planning committee at school has 10 members. Exactly four of these members are teachers. A four-person subcommittee with at
Kipish [7]

Answer:

865

Step-by-step explanation: The set of possibilities are:

Subcommittee  is of 4 people according to:

4  teachers    0 other member       total possibilities    1

3  teachers     1     teachers  C₄,₃  = 4   and  other member  6    6*4   =  24

2 teachers     2      C₄,₂  =  4!/2!  = 12    2 (om)    and  C₆,₂   =  6!/4!  = 30

30*12  = 360

1  teacher        3     (om)               4         and  C₆,₃ = 6!/3!   =  120

120*4  = 480

Total ways of committee    1  + 24  + 360 +  480  = 865

4 0
3 years ago
I don’t know how to do this. can someone please help me :)
Kaylis [27]
The surface area of a cylinder is the sum of the area of the two ends and the lateral area.
.. surface area = 2*(end area) +(lateral area)
.. = 2*(π*r^2) +(2π*r*h)
.. = 2π*r*(r +h)
.. = 2*3.14*(8 in)*(8 in +8 in)
.. = 3.14*256 in^2
.. ≈ 803.8 in^2

The 3rd selection is appropriate.
8 0
4 years ago
Referring to the Fig. in Question #40, find the unknown<br> length Y.
icang [17]

Answer:

tan30°=7/x

\frac{1}{ \sqrt{3} }  =  \frac{7}{x }  \\ x = 7 \sqrt{3}

cos30°=x/y

\frac{ \sqrt{3} }{2}   =  \frac{7 \sqrt{3} }{y}  \\  \\ 7 \sqrt{3}  \times 2 =  \sqrt{3}  \times y \\ \frac{7 \sqrt{3 }  \times 2}{ \sqrt{3} }  = y \\7 \times 2 = y \\ 14 = y

tell me if it's wrong.

7 0
2 years ago
Read 2 more answers
The biggest zucchini from Joe's farm is 2 pounds, which is 1
Vera_Pavlovna [14]

Step-by-step explanation:

It means average weight of zucchinis is 1 pound because 2 - 1 = 1

4 0
3 years ago
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