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Draw Conclusions Suppose that A and C are real numbers and A is not 0. What are the x- and y-intercepts of the equation Ay = C?

Iteru [2.4K]

Answer:

Horizontal line which goes through the y -axis at the coordinate ( 0, C/A ).

Step-by-step explanation:

Since A is not 0 then C can not be 0 This is a logical deduction from the given formula Ay = C

The equation of any line is y = ax + b, where a is the incline and b is the intercept between the line and the y- axis.

Ay = C

Divide left and right of the = sign by A and you get:

y = C/A

This is the formula for a horizontal line which goes through the y -axis at the coordinate ( 0, C/A ).

Because it is a horizontal line it has an incline of 0.

So a = 0

y = ax + b

a = 0 and b = C/A

y = 0*x + C/A

y = 0 + C/A

y = C/A

7 0

3 years ago

7 names with a median length of 14 letters

SpyIntel [72]

Sue Ann, Mary Anne, Abigail Adams, Johnathan Smith, Carlitos Jimenez, Mary-Sue Marionette, Estaban Julio Ricardo Montoya Delarosa Ramirez

I think.... If i'm not mistaken, that should work.

3 0

3 years ago

Office occupancy in a city is an indication of the economic health of the region in which it is located. A random sample of offi

Pani-rosa [81]

Answer:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

Step-by-step explanation:

$p_1$ represent the real population proportion for 1

$\hat p_1 =\frac{22}{165}=0.13$ represent the estimated proportion for 1

$n_1=165$ is the sample size required for 1

$p_2$ represent the real population proportion for 2

$\hat p_2 =\frac{14}{140}=0.10$ represent the estimated proportion for 2

$n_2=140$ is the sample size required for 2

$z$ represent the critical value for the margin of error

The confidence interval for the difference of two proportions would be given by this formula

$(\hat p_1 -\hat p_2) \pm z_{\alpha/2} \sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1} +\frac{\hat p_2 (1-\hat p_2)}{n_2}}$

For the 99% confidence interval the significance is $\alpha=1-0.99=0.01$ and $\alpha/2=0.005$ , and the critical value using the normal standard distribution.

$z_{\alpha/2}=2.58$

Replacing we got:

$(0.13-0.1) - 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=-0.0664$

$(0.13-0.1) + 2.58 \sqrt{\frac{0.13(1-0.13)}{165} +\frac{0.10(1-0.10)}{140}}=0.124$

We are confident at 99% that the difference between the two proportions is between $-0.0664 \leq p_1 -p_2 \leq 0.124$ . And since the confidence interval cotains the value 0 we don't have enough evidence to conclude that we have significant differences between the to proportions in these two cities

8 0

3 years ago

Evaluate the expression for the given values.

Igoryamba

Answer:

a is 39

b is 57

Step-by-step explanation:

you were given two different expressions to substitute.

the first one is p = 8 and d = 1/7

so we substitute into 5p - 7d

that is 5(8) - 7(1/7)

we get 40 - 1

which if we go ahead to evaluate we get 39

The second one p = 3 and d = -6

so we get 5(3) - 7(-6)

we get 15 - (-42)

if we go ahead to evaluate we get 15 + 42

two negative meeting each other gives you positive.

then it going too be 57

7 0

2 years ago

Ms. Jenkins stocks a pond with fish. For every 6 bluegill fish, she puts in 1 rock bass fish. Does this ratio mean that Ms. Jenk

snow_tiger [21]

Answer:

Ms. Jenkins puts <u>for every 6</u> bluegill fish <u>one</u> rock bass fish so she puts the number multiple of 7

6 0

3 years ago