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Galina-37 [17]
3 years ago
5

I need help with this one and 4 more!!!

Mathematics
1 answer:
Nitella [24]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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F. 10, 20, 30, 40, 50

Step-by-step explanation:

Becasue Y is the dependent varible  

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3 years ago
What is the probability that a randomly selected member of a normally distributed population will lie more than 1.8 standard dev
Helen [10]

Answer:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution to the problem

Let X the random variable that represent the variable if interest of a population, and for this case we know the distribution for X is given by:

X \sim N(\mu,\sigma)  

We are interested on this probability

P(X>\mu +1.8 \sigma)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X> \mu +1.8\sigma)=P(\frac{X-\mu}{\sigma}>\frac{\mu +1.8\sigma-\mu}{\sigma})=P(Z>1.8)

And we can find this probability using the complement rule:

P(z>1.8)=1-P(z

And using the normal standard distirbution table or excel we got:

P(z>1.8)=1-P(z

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4 years ago
How much will it cost to ride if the cab travels 13.5 miles?
MrMuchimi
Please provide more information. This question is not able to be answered with the information provided. Try giving the full problem!
6 0
3 years ago
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