Answer:
![\sqrt[3]{x^{10} }[\tex]Step-by-step explanation:Exponential Rules:[tex]x^{a} + x^{b} = x^{a + b}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3E%3Cstrong%3EStep-by-step%20explanation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EExponential%20Rules%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5Dx%5E%7Ba%7D%20%2B%20x%5E%7Bb%7D%20%3D%20x%5E%7Ba%20%2B%20b%7D)
![\sqrt[b]{x^{a} } =x^{\frac{a}{b} } Original Equation:[tex]\sqrt[3]{x^{10} } = x^{\frac{10}{3} } Answer:[tex]\sqrt[3]{x^{10} }[\tex]Convert the cubed root to a power. Cubed root = [tex]\frac{1}{3}](https://tex.z-dn.net/?f=%5Csqrt%5Bb%5D%7Bx%5E%7Ba%7D%20%7D%20%3Dx%5E%7B%5Cfrac%7Ba%7D%7Bb%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EOriginal%20Equation%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%20%20%3D%20x%5E%7B%5Cfrac%7B10%7D%7B3%7D%20%7D%20%3C%2Fp%3E%3Cp%3E%3C%2Fp%3E%3Cp%3E%3Cstrong%3EAnswer%3A%3C%2Fstrong%3E%3C%2Fp%3E%3Cp%3E%5Btex%5D%5Csqrt%5B3%5D%7Bx%5E%7B10%7D%20%7D%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3EConvert%20the%20cubed%20root%20to%20a%20power.%20Cubed%20root%20%3D%20%5Btex%5D%5Cfrac%7B1%7D%7B3%7D)

Convert them, so they have a common denominator - 


[tex]\sqrt[3]{x^{10} }[\tex] = [tex]x^{\frac{10}{3} } [\tex]
Answer:
They are similar because their corresponding angles are congruent and their corresponding sides are proportional in length.
Step-by-step explanation:
From the statements,
∠G≅∠K
∠F≅∠J
∠H≅∠L
The sides of triangle FGH are proportional to those of triangle JKL
FG/JK =GH/KL=FH/JL =1/2
Answer:
6.1
Step-by-step explanation:
Taking cos function,
Cos C=BC/AC
Cos 35°=5/a
a=5/cos 35°
a=6.1
Answer:
-1
Step-by-step explanation:
You can find the average my finding the sum of all temperatures and then dividing it by the number of temperatures ( in this case 7)
So you get (-3-5+3+7-2-2-5)/7=-7/7=-1