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3 years ago

Solve. 9(4h - 6) = 2( -13 - 2h)

Mathematics

2 answers:

Olin [163]3 years ago

8 0

Answer:

h= 7/10

Step 1: Remove the parentheses

9(4h - 6) = 2( -13 - 2h) = 36h-54= -26 -4h

Step 2: Move the terms

36h-54= -26 -4h = 36h+4= -26 + 54

Step 3: Calculate like terms

36h+4= -26 + 54 = 40h=28

Step 4: Divide both sides

40h=28 = h= 7/10

(In decimal form - h=0.7)

Afina-wow [57]3 years ago

6 0

Answer: h= 7/10

Step-by-step explanation:

9(4h - 6 ) = 2(-13 - 2h) Distribute on both sides

9(4h) + 9(-6) = 2(-13) + 2(-2h)

36h - 54 = -26 - 4h Add 4h to both sides

+4h +4h

40h - 54 = -26 Add 54 to both sides

+54 +54

40h = 28 Divide both sides by 40

h = 7/10

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Answer:

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Step-by-step explanation:

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ratelena [41]

By the definition of the hyperbolic function tanh x, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

<h3>Hyperbolic functions & Proof of identities </h3>

By definition

$tanh \ x=\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}}$

Then,

$\frac{1-tanh \ x}{1 + tanh \ x}=\frac{1-\frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }{1+ \frac{e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

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$=\frac{e^{x} +e^{-x}-e^{x} +e^{-x}}{e^{x} +e^{-x}} \div \frac{e^{x} +e^{-x}+e^{x} -e^{-x}}{e^{x} +e^{-x}} }$

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$=\frac{2e^{-x}}{e^{x} +e^{-x}} \div \frac{2e^{x} }{e^{x} +e^{-x}} }$

$=\frac{2e^{-x}}{e^{x} +e^{-x}} \times \frac{e^{x} +e^{-x}}{2e^{x}}$

$=\frac{2e^{-x}}{1} \times \frac{1}{2e^{x}}$

$=\frac{2e^{-x}}{2e^{x}}$

$=\frac{e^{-x}}{e^{x}}$
$=e^{-x} \times \frac{1}{e^{x}}$

$= e^{-x} \times e^{-x}$

$= e^{-x+-x}$

$= e^{-x-x}$

$= e^{-2x}$

Hence, we have proven that $\frac{1-tanh \ x}{1 + tanh \ x}=e^{-2x}$

Learn more on Proof of Identities here: brainly.com/question/2561079

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