1.) So 1/5 of a relay, or r, is 3/4 of a mile.
1/5r = 3/4
Multiply 5 on both sides of the equation.
r = 15/4
The relay was 15/4 of a mile or 3 3/4 of a mile.
2.) No, it is not because the sum of the digits are not divisible by 3.
Hope this helps! :)
Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Pre-Calculus</u>
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
![\frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
- Trig Derivative:
![\frac{d}{dx} [cos(x)] = -sin(x)](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcos%28x%29%5D%20%3D%20-sin%28x%29)
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
4y + 3 > 23 subtract 3 from both sides
4y > 20 divide both sides by 4
y > 5
-2y > -2 divide both sides by -2 (the order changes)
y < 1
(-oo, 1) ∪ (5, oo)
Upvote
SO SORRY IF THESE IS WRONG:(( JUST SAY IT TO ME NOT TO BULLY ME
QUESTION 1
The given system of equations are:


We equate the two equations to get:




When x=0,

The solution is (0,1)
QUESTION 2
The given equations are:

and

We equate both equations to get:

Group similar terms,



We put x=0 into any of the equations to find y.

The solution is (0,-1).
QUESTION 3
The given equations are:

and

We equate both equations:

Group similar terms:


This is not true.
Hence the system has no solution.