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Sladkaya [172]
3 years ago
12

Can someone explain how a compass and straight-edge allow us to “measure” segments and angles. This is for Geometry... Thank you

!
Mathematics
1 answer:
Salsk061 [2.6K]3 years ago
6 0

Answer:

just typing random stuff so i dont have to watch adds -,-

Step-by-step explanation:

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Please help me with this. ​
masya89 [10]

Answer:

a) 48 b) 132 c) 180 d) 228 e) 312

Step-by-step explanation:

3 0
3 years ago
The lifespan (in days) of the common housefly is best modeled using a normal curve having mean 22 days and standard deviation 5.
Natasha_Volkova [10]

Answer:

Yes, it would be unusual.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

If Z \leq -2 or Z \geq 2, the outcome X is considered unusual.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

In this question, we have that:

\mu = 22, \sigma = 5, n = 25, s = \frac{5}{\sqrt{25}} = 1

Would it be unusual for this sample mean to be less than 19 days?

We have to find Z when X = 19. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{19 - 22}{1}

Z = -3

Z = -3 \leq -2, so yes, the sample mean being less than 19 days would be considered an unusual outcome.

7 0
3 years ago
Please see attachment for the question.
Sophie [7]

Step-by-step explanation:

\frac{10 {x}^{3}  -  12 {x}^{2}   + 6x - 7 }{ - 14 {x}^{2} - 1 }

-14x²-1≠0

x²≠ -1/14

Option C

5 0
4 years ago
What is the solution?
galina1969 [7]

Answer:

y=60 x=16

Step-by-step explanation:

the triangles are identical so 92+y=3y-28 so solve that for y:

                                                     -y      +28

                                                  120=2y                                                                            .                                                  /2      /2

                                                  60 = y so y=60

and 6x+2=3x+50 and solve that for x: which gets x = 16

Then are you supposed to plug it in to the numerical equvilant to the angles and sides becuase if so:  B and E is 152, AC and DF are 98

Hope this helps and brainliest would be greatly appreciated! Thanks!

4 0
3 years ago
What is the most appropriate level of accuracy for measuring the height of a tree
elena55 [62]

Answer:

Step-by-step explanation:

Depends on the tree.

If it's like a pine or spruce, then I would use maybe 2 inches lattitude. If it's really leafy with big leaves, perhaps a little more lattitude is needed, like maybe 1/2 a foot.

It also depends on the season. Unless the pine or spruce is covered with snow, I wouldn't change the latitude. If it is covered with snow, knock the snow off.

For something like a maple in winter, I'd reduce the latitude to 3 inches......

6 0
3 years ago
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