Question

What is the equation of the line that passes through the points 1,2/3 and -1,-1

Answer 1

(1,2/3)(-1,-1)
slope = (-1 - 2/3) / (-1 - 1) = (-3/3 - 2/3) / (-2) = (-5/3) / -2 = -5/3 * - 1/2 = 5/6

y = mx + b
slope(m) = 5/6
(-1,-1)..x = -1 and y = -1
now we sub and find b, the y int
-1 = 5/6(-1) + b
-1 = - 5/6 + b
-1 + 5/6 = b
-6/6 + 5/6 = b
-1/6 = b

so ur equation is : y = 5/6x - 1/6