Using the z-distribution, it is found that since the <u>test statistic is more than the critical value for the left-tailed test</u>, it is found that there is not enough evidence to conclude that illegal drug use in her school is below the current national average.
At the null hypothesis, it is <u>tested if drug use in her school is not below the national average</u>, that is:
At the alternative hypothesis, it is <u>tested if it is below</u>, that is:
The test statistic is given by:
In which:
- is the sample proportion.
- p is the proportion tested at the null hypothesis.
93 out of 1046 reported using illegal drugs, hence the parameters are:
Hence, the value of the <em>test statistic</em> is:
The critical value for a <u>left-tailed test</u>, as we are testing if the proportion is less than a value, is
Since the <u>test statistic is more than the critical value for the left-tailed test</u>, it is found that there is not enough evidence to conclude that illegal drug use in her school is below the current national average.
To learn more about the use of the z-distribution to test an hypothesis, you can take a look at brainly.com/question/25584945