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3 years ago

7

6 first-year teachers and 4 experienced teachers attended a school staff meeting meeting. What percentage of the teachers in the

meeting were first-year teachers?

2 answers:

Jobisdone [24]3 years ago

7 0

60%
if you add 6 and 4 together it would make 10 and 6 percent of 10 is 60%

Marina CMI [18]3 years ago

4 0

60%
6 first year
4 experienced
add them = 10
since six are first year u get 60%

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Scilla [17]

Area = S^2

S(S-3) =70

S^2 -3S = 70
S^2 - 3s-70 = 0

(s-10) (s+7) = 0

s = 10, s=-7

S=10

original dimension was 10cm x 10cm

3 0

3 years ago

what are the length and width of a rectangular traffic sign if the length exceeds the width by 24 inches and the perimeter by 12

madreJ [45]

Answer:

<h2>length = 44 in, width = 20 in</h2>

Step-by-step explanation:

$\text{The formula of a perimeter of a rectangle:}\\\\P=2(l+w)\\\\l-length\\w-width\\\\\text{We have}\ l=(w+24)\ in,\ P=128\ in\\\\\text{Substitute:}\\\\128=2(w+24+w)\qquad\text{divide both sides by 2}\\\\64=2w+24\qquad\text{subtract 24 from both sides}\\\\40=2w\qquad\text{divide both sides by 2}\\\\20=w\to w=20\ in\\\\l=20+24=44\ in$

7 0

3 years ago

Tv emporium had a huge sale in the morning 5/12 of the flat screen televisions were sold in the afternoon one-third of the flat

lara [203]

Answer:

Total number of flat screen sold is 3/4

Step-by-step explanation:

Let the total number of the flat screen sold be y

y = number of flat screen sold in the morning + number of the flat screen sold in the afternoon.

Number sold in the morning = 5/15

Number sold in the afternoon = 1/3

Y = 5/12 + 1/3

Find the LCM of 12 and 3

Y = (5 + 4)/12

Y = 9/12

Y = 3/4

Total number of flat screen sold is 3/4

3 0

3 years ago

Read 2 more answers

What is the ethnic makeup of Brazil

siniylev [52]

Answer:

white 47.7%, mulatto (mixed white and black) 43.1%, black 7.6%, Asian 1.1%,

Step-by-step explanation:

white 47.7%,

mulatto (mixed white and black)

43.1%, black 7.6%,

Asian 1.1%,

5 0

4 years ago

Read 2 more answers

A simple random sample from a population with a normal distribution of 103 body temperatures has x overbarequals98.90degrees Upp

Shtirlitz [24]

Answer:

$98.90-1.984\frac{0.62}{\sqrt{103}}=96.98$

$98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82$

The 95% confidence interval would be given by (96.98;100.82)

Step-by-step explanation:

Information given

$\bar X=98.90$ represent the sample mean

$\mu$ population mean (variable of interest)

s=0.62 represent the sample standard deviation

n=103 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=103-1=102$

Since the Confidence is 0.95 or 95%, the significance is $\alpha=0.05$ and $\alpha/2 =0.025$ , and the critical value for this case would be $t_{\alpha/2}=1.984$

And replacing we got:

$98.90-1.984\frac{0.62}{\sqrt{103}}=96.98$

$98.90+ 1.984\frac{0.62}{\sqrt{103}}=100.82$

The 95% confidence interval would be given by (96.98;100.82)

8 0

4 years ago