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Fantom [35]
3 years ago
7

6 first-year teachers and 4 experienced teachers attended a school staff meeting meeting. What percentage of the teachers in the

meeting were first-year teachers?
Mathematics
2 answers:
Jobisdone [24]3 years ago
7 0
60%
if you add 6 and 4 together it would make 10 and 6 percent of 10 is 60%
Marina CMI [18]3 years ago
4 0
60%
6 first year
4 experienced
add them = 10
since six are first year u get 60%
You might be interested in
Help
BigorU [14]

Answer:

69

thats it all of them are 69

4 0
3 years ago
8s + 9 = 7s + 6 <br>s= ? ​
denis-greek [22]

Answer:

s = -3

Step-by-step explanation:

8s + 9 = 7s + 6

Subtract 7s from each side

8s-7s + 9 = 7s-7s + 6

s+9 = 6

Subtract 9 from each side

s + 9-9 =   6-9

s = -3  

7 0
3 years ago
Read 2 more answers
If A(-5,7), B(-4,-5), C(-1,-6) and D(4,5) are the vertices of a quadrilateral, find the area of the quadrilateral ABCD.
MrMuchimi
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.

The area of a triangle with vertices known is  given by the matrix
M = \left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]

Area = 1/2· | det(M) |
        = 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
        = 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |

Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
             = 1/2· | -5·(1) - 4·(-13) - 1·(12) |
             = 1/2 | 35 |
             = 35/2

Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
             = 1/2· | -5·(11) + 4·(-13) - 1·(2) |
             = 1/2 | -109 |
<span>             = 109/2</span>

The total area of the quadrilateral will be the sum of the areas of the two triangles:

A(ABCD) = A(ABC) + A(ADC) 
               = 35/2 + 109/2
               = 72
8 0
4 years ago
NEED HELP ASAP PLEASE
olga55 [171]
I think it's reflected and dilated.

5 0
3 years ago
Read 2 more answers
If the test scores in Personal Finance Unit 9 are normally distributed with a
nasty-shy [4]

Answer:

68.269%

Step-by-step explanation:

We start by calculating the z-scores of both numbers

Mathematically;

z-score = (x-mean)/SD

where x represents the raw score

For 82;

z-score = (82-87)/5 = -5/5 = -1

For 92;

z-score = (92-87)/5 = 5/5 = 1

So the probability we want to calculate would be;

P(-1 < x< 1)

We can use the standard normal distribution table to get this.

By using the distribution, P(-1<x<1) = 0.68269

By converting this to percentage, we have 68.269%

3 0
3 years ago
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