Answer:
El precio del saco del azúcar es de 72.
Step-by-step explanation:
Sean
,
los precios del saco de arroz y el saco de azúcar, respectivamente. A continuación, traducimos cada oración relevante en ecuaciones matemáticas:
(i) <em>El precio del saco de arroz es a 2 como el precio del saco de azúcar es a 3</em>:
Aquí se menciona una igualdad entre expresiones racionales, es decir:
![\frac{x}{2} = \frac{y}{3}](https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7B2%7D%20%3D%20%5Cfrac%7By%7D%7B3%7D)
(1)
(ii) <em>El producto de ambos precios es numéricamente 3456</em>:
(2)
Ahora resolvemos el sistema de ecuaciones, despejamos
en (1):
![x = \frac{2}{3}\cdot y](https://tex.z-dn.net/?f=x%20%3D%20%5Cfrac%7B2%7D%7B3%7D%5Ccdot%20y)
Y la aplicamos en (2):
![\frac{2}{3}\cdot y^{2} = 3456](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D%5Ccdot%20y%5E%7B2%7D%20%3D%203456)
![y^{2} = 5184](https://tex.z-dn.net/?f=y%5E%7B2%7D%20%3D%205184)
![y = 72](https://tex.z-dn.net/?f=y%20%3D%2072)
El precio del saco del azúcar es de 72.
Answer: If you are asking for the reflection, it will be (-2,3)
Step-by-step explanation:
Hope I helped!
1120000000000000000
Hope this helps
The answer is 1487.9286. hope you have a good day or night.
Answer:
47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth
Step-by-step explanation:
For each individual, there are only two possible outcomes. Either they cover their mouth when sneezing, or they do not. The probability of an individual covering their mouth when sneezing is independent of other individuals. So we use the binomial probability distribution to solve this question.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
In which
is the number of different combinations of x objects from a set of n elements, given by the following formula.
![C_{n,x} = \frac{n!}{x!(n-x)!}](https://tex.z-dn.net/?f=C_%7Bn%2Cx%7D%20%3D%20%5Cfrac%7Bn%21%7D%7Bx%21%28n-x%29%21%7D)
And p is the probability of X happening.
According to a study done by Otago University, the probability a randomly selected individual will not cover his or her mouth when sneezing is 0.267.
This means that ![p = 0.267](https://tex.z-dn.net/?f=p%20%3D%200.267)
What is the probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth
10 individuals, so n = 10.
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29)
In which
![P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}](https://tex.z-dn.net/?f=P%28X%20%3D%20x%29%20%3D%20C_%7Bn%2Cx%7D.p%5E%7Bx%7D.%281-p%29%5E%7Bn-x%7D)
![P(X = 0) = C_{10,0}.(0.267)^{0}.(0.733)^{10} = 0.0448](https://tex.z-dn.net/?f=P%28X%20%3D%200%29%20%3D%20C_%7B10%2C0%7D.%280.267%29%5E%7B0%7D.%280.733%29%5E%7B10%7D%20%3D%200.0448)
![P(X = 1) = C_{10,1}.(0.267)^{1}.(0.733)^{9} = 0.1631](https://tex.z-dn.net/?f=P%28X%20%3D%201%29%20%3D%20C_%7B10%2C1%7D.%280.267%29%5E%7B1%7D.%280.733%29%5E%7B9%7D%20%3D%200.1631)
![P(X = 2) = C_{10,2}.(0.267)^{2}.(0.733)^{8} = 0.2673](https://tex.z-dn.net/?f=P%28X%20%3D%202%29%20%3D%20C_%7B10%2C2%7D.%280.267%29%5E%7B2%7D.%280.733%29%5E%7B8%7D%20%3D%200.2673)
![P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0448 + 0.1631 + 0.2673 = 0.4752](https://tex.z-dn.net/?f=P%28X%20%3C%203%29%20%3D%20P%28X%20%3D%200%29%20%2B%20P%28X%20%3D%201%29%20%2B%20P%28X%20%3D%202%29%20%3D%200.0448%20%2B%200.1631%20%2B%200.2673%20%3D%200.4752)
47.52% probability that among 10 randomly observed individuals fewer than 3 do not cover their mouth