Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer:
-9.5-42.1/6=x
-8.6
-9.5+ 6x-8.5
-61.1
Step-by-step explanation:
Answer: C=t+50
Step-by-step explanation: This equation means that Clare's score equals Tyler's score plus 50.
Only one choice is correct here.
Answer:
x = 3
Step-by-step explanation:
The external angle of a triangle is equal to the sum of the 2 opposite interior angles
∠ QRT is an external angle, thus
∠ QRT = ∠ RTS + ∠ RST, substitute values
45x = 25x + 57 + x
45x = 26x + 57 ( subtract 26x from both sides )
19x = 57 ( divide both sides by 19 )
x = 3
Answer:
there 3x and 4y hope this makes sense ik on a rush
