Prove that if m + n and n + p are even integers, where m, n, and p are integers, then m + p is even.
m=2k-n, p=2l-n
Let m+n and n+p be even integers, thus m+n=2k and n+p=2l by definition of even
m+p= 2k-n + 2l-n substitution
= 2k+2l-2n
=2 (k+l-n)
=2x, where x=k+l-n ∈Z (integers)
Hence, m+p is even by direct proof.
The volume, fr I don’t rly know sry
Answer:
0.9
Step-by-step explanation:
Given that , Length of Base and Hypotenuse is 12 cm and 24 cm , respectively .
Need To Find : The measure of Angle x .
<em>As </em><em>We </em><em>know </em><em>that </em>,
Cos ∅ = Base / Hypotenuse
ㅤㅤ <u>By </u><u>Substituting </u><u>known </u><u>Values </u><u>:</u>
ㅤ⤀Cos x = 12/24
ㅤ⤀Cos x = ½
ㅤ⤀Cos 60⁰ = ½
Therefore,
Answer:
a
Step-by-step explanation:
hope this will help u.........
