How does one explain how to graph a point on the coordinate grid?

Mathematics

1 answer:

Neko [114]3 years ago

8 0

Answer:

Firstly you have to know the x and y points,

then you use the coordinate grid to plot the points and then draw the graph from the points that has been plotted.

Hopefully this helps :)

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The sum of two polynomials is 10a^2b^2-8a^2b+6ab^2-4ab+2 if one addend is -5a^2b^2+12a^2b-5 what is the other addend

spayn [35]

Answer:

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

Step-by-step explanation:

The other addend is determined by subtracting $-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b-5$ from $10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a\cdot b^{2}-4\cdot a \cdot b + 2$ :

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b + 2 - (-5\cdot a^{2}\cdot b^{2}+12\cdot a^{2}\cdot b -5)$

$x = 10\cdot a^{2}\cdot b^{2}-8\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +2 +5\cdot a^{2}\cdot b^{2}-12\cdot a^{2}\cdot b+5$

$x = (10\cdot a^{2}\cdot b^{2}+5\cdot a^{2}\cdot b^{2})-(8\cdot a^{2}\cdot b+12\cdot a^{2}\cdot b)+6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

$x = 15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$

The other addend is $15\cdot a^{2}\cdot b^{2}-20\cdot a^{2}\cdot b + 6\cdot a \cdot b^{2}-4\cdot a \cdot b +7$ .

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Which sentence is a example of the distributive property ? AND WHY!!!?

katrin [286]

Answer:

answer is C

Step-by-step explanation:

Because it gives clear distribution process.

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3 years ago

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kvv77 [185]

The line that maps a figure onto itself is a line of symmetry of the figure.

From the given trapezoid, the line of symmetry of the trapezoid is x = -2.

Therefore, the <span>equation for the line of reflection that maps the trapezoid onto itself</span> is x = -2.

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What is the area of the rhombus?

IRINA_888 [86]

The area of rhombus is 24 square units.

Step-by-step explanation:

Given,

Length of one diagonal = p = 3+3 = 6 units

Length of other diagonal = q = 4+4 = 8 units

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