Answer:
20ln(3)
Step-by-step explanation:
Put 15 for A and solve for t.
15 = 45e^(-.05t)
15/45 = 1/3 = e^(-.05t) . . . . divide by 45
ln(1/3) = -.05t . . . . . . . . . . . take natural logs
20ln(3) = t . . . . . . . . . . . . . . multiply by 20, simplify
It will take 20·ln(3) years for the area to decrease to 15 km^2.
Answer:
The second one:
L∪J={i,j,k,l,m,n,o}
Step-by-step explanation:
The union is the elements listed in either set.
So since l,m,n, and o are elements of set L, they will also be elements of whatever it is "unioned" with.
Since i,j,k,l and m are elements of set J, they will also be elements of whatever it is "unioned" with.
When you write the union, just be sure to include each element that occurs in either set once.
So the union of L and J is {i,j,k,l,m,n,o}.
The answer is the second one.
The intersection would actually be that upside down U thing, the ∩ symbol. The intersection of two sets is a list of elements that both sets include. So here the intersection would just consist of the elements l amd m.
Find (-4) on the number line and move 3 to the right. You will end up at (-1).
Find (3) on the number line and move 4 to the left. You will end up at the same value of (-1).
Answer:
k= 5.6
Step-by-step explanation:
